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3 years ago

5

A cube of gold weights1.89N when suspended in air from a spring scale. When suspended in molasses, it appears to weight 1.76 N.

What is the bouyancy force acting on the cube? Do you think the buoyancy force would bengreater or smaller if the gold cube were suspended in water?

1 answer:

Eddi Din [679]3 years ago

3 0

smaller depending on friction and aiming of the gold cube

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Can you travel faster by not running forward ?

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a block with a mass of 3 kg is swung on a cord in a horizontal circle with a radius of 2m. the speed of the block is 6m/s^. the

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Given Information:

Mass = m = 3 kg

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Required Information:

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Answer:

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Explanation:

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a = v²/r

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Bonus:

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Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

The amplitude of the lateral force is $F = 25 \ N$

The frequency is $f = 1 \ Hz$

The mass of the bridge per unit length is $\mu = 2000 \ kg /m$

The length of the central span is $d = 144 m$

The oscillation amplitude of the section considered at the time considered is $A = 75 \ mm = 0.075 \ m$

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Generally the oscillation amplitude of the section after a time period t is mathematically represented as

$A(t) = A_o e^{-\frac{bt}{2m} }$

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$\frac{A_o}{e} = A_o e^{-\frac{b6T}{2m} }$

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=> $e^{-1} =e^{-\frac{b6T}{2m} }$

=> $-\frac{3T b}{m} = -1$

=> $b = \frac{m}{3T}$

Generally the amplitude of the section considered is mathematically represented as

$A = \frac{n * F }{ b * 2 \pi }$

=> $A = \frac{n * F }{ \frac{m}{3T} * 2 \pi }$

=> $n = A * \frac{m}{3} * \frac{2\pi}{25}$

=> $n = 0.075 * \frac{288000}{3} * \frac{2* 3.142 }{25}$

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Answer:

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