A car with a velocity of 6.4 m/s, forward, accelerates to a velocity of 10.6 m/s, forward, in 16 s. What is the card acceleratio
2 answers:
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The velocity of the particle is given by the derivative of the position vector:
(a) The particle is moving in the <em>x</em>-direction when the <em>y</em>-component of velocity is zero:
But we want <em>t</em> > 0, so this never happens, unless 2<em>c</em> = <em>d</em> is given, in which case the <em>y</em>-component is always zero.
(b) Similarly, the particle moves in the <em>y</em>-direction when the <em>x</em>-component vanishes:
We drop the zero solution, and we're left with
In the case of 2<em>c</em> = d, this times reduces to <em>t</em> = <em>c</em>/(6<em>c</em>) = 1/6.