1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
julia-pushkina [17]
3 years ago
14

A car with a velocity of 6.4 m/s, forward, accelerates to a velocity of 10.6 m/s, forward, in 16 s. What is the card acceleratio

n
Physics
2 answers:
tatuchka [14]3 years ago
6 0

Answer:

acceleration = 0.2625 m/s²

Explanation:

   acceleration = ( final velocity - initial velocity ) / time

Here the final velocity is  10.6 m/s and initial velocity is 6.4 m/s and time is 16 s.

using the equation:

acceleration =  ( 10.6 - 6.4 ) / 16

                     = 0.2625 m/s²

Helga [31]3 years ago
3 0

Answer:

V0= 6.4 m/s\\V1= 10.6 m/s\\t = 16s\\V1 = V0 + a.t\\10.6 - 6.4 = a.16\\a=\frac{4.2}{16} \\a=0,2625 m/s^{2}

Explanation:

You might be interested in
Determine the kinetic energy of a 55kg woman running with the velocity of 5.87m/s
Greeley [361]
The formula for kinetic energy = ½m·v<span>2

1/2 * 55 kg x 5,87 m/s ^2 = 27.5 x </span>34.4569 = <span>947.56475 Joule </span>≈ 948 J
4 0
3 years ago
Why does a black hole have a stronger gravitational pull than the star that collapse to form it?​
Studentka2010 [4]

Answer:

We consider Black Holes as an object that possesses extreme gravitational pull, but wait aren’t they have the same mass(or less) as that of their parent star. And we know that gravitational pull ‘F’ is directly proportional to the mass of an object, so if the mass is same(or less) then why do black holes have stronger gravity than the stars they evolved from.

The above consideration that F is directly proportional to the mass is partially correct, one should also mention that F is also inversely proportional to the square of the distance between the considered objects.

F = G*(M*m)/(r^2)

Where:

· F is the force acting on you due to star

· M is the mass of Parent star / Black Hole

· m is the mass of an observer, here it is you

· r is the radial distance between the star and you

We know that black hole formed, has much smaller size than that of its parent star and all that mass is compressed to a much smaller scale. If you consider a Star as having a size of an earth then the black hole formed will have a size of small city.

Let us say that you are standing at an r distance away from a star (r>R1), where R1 is the radius of the star, of course (R1>R2), where R2 is the radius of Black Hole.

The Force by which the star in case 1 attracts you will be equal(or less) to the force by which black hole in case 2. So, there is nothing increase in gravitational pull, it is same(or less) as that of the parent star.

Wait a minute, then why people say that black holes have massive gravitational pull.

The gravitational pull increases as we move closer to the black hole, and when we are at its surface, it is enormous as compare to its star surface, because of the difference in the size.

We know that gravitational pull not only depends upon the mass but also depends upon the radial distance between the concerned objects here, it is you and the black hole.

Here, the size of the black hole is much smaller than that of its parent star, i.e (R1>>>R2), and thus we get F1<<<F2, and that is why we say that the black hole has enormous gravitational pull, such that nothing can escape, not even light.

8 0
3 years ago
You drive your car in a straight line at 15 m/s for 10 kilometers, then at 25 m/s for another 10 kilometers.
Vikki [24]

Answer:

A) Average speed = 18.75 m/s

B) More time is spent at 15 m/s than at 25 m/s.

Explanation:

Let the first distance be d1 and the second distance be d2.

We are given;

d1 = 10 km = 10000 m

d2 = 10 km = 10000 m

Speed; v1 = 15 m/s

Speed; v2 = 25 m/s

Now, the formula for distance is; Distance = speed x time

Thus:

d1 = v1 x t1

t1 = d1/v1 = 10000/15 = 666.67 seconds

Also,

d2 = v2 x t2

t2 = d2/v2 = 10000/25 = 400 seconds

Average speed = total distance/total time = (10000 + 10000)/(666.67 + 400) = 18.75 m/s

From earlier, since t1 = 666.67 seconds and t2 = 400 seconds, then;

More time at 15 m/s than at 25 m/s.

5 0
4 years ago
What's the minimum Out PUT WORK<br> required to raise 14,0m3 of water 26.0m?
BartSMP [9]

Answer:

3.57 MJ

Explanation:

ASSUMING it's fresh water with density of 1000 kg/m³

W = ΔPE = mgΔh = 14.0(1000)(9.81)(26.0) = 3,570,840 J

Salt water would require more.

3 0
3 years ago
A gas is collected from a radioactive material; upon inspection, the gas is identified as helium. the presence of the helium ind
Flura [38]
The presence of helium gas indicates the radioactive sample is most likely decaying by α-decay, or alpha decay. α-decay is the type of radioactive decay in which an atomic nucleus emits α particles. α particles are Helium nuclei. So the correct answer would be α-decay.
7 0
3 years ago
Other questions:
  • Which expression is dimensionally consistent with anexpression that would yield a value for time-1?(v is velocity, x is distance
    10·1 answer
  • An inductance L, resistance R, and ideal battery of emf are wired in series. A switch in the circuit is closed at time t = 0, at
    13·2 answers
  • Which of the following phases of the Moon produces the highest and lowest tides on Earth?
    7·2 answers
  • What properties of Pluto might make scientists think that it is a Kuiper Belt Object?
    9·1 answer
  • What is the meaning of overall charge.
    12·1 answer
  • Projectile motion physics question 11 please​
    11·1 answer
  • How does ATP affect your body during exercise
    9·1 answer
  • A spring with constant 559 N/m is 0.14 meters long when not stretched or compressed. You compress the spring until it is 0.07 me
    7·1 answer
  • What will be the ratio of distances between the two charges of each pair of charges (1µC, 2µC) and (2µC, -3uC) so that force her
    10·1 answer
  • a force pushes the cart for 1 s, starting from rest. to achieve the same speed with a force half as big, the force would need to
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!