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julia-pushkina [17]
2 years ago
14

A car with a velocity of 6.4 m/s, forward, accelerates to a velocity of 10.6 m/s, forward, in 16 s. What is the card acceleratio

n
Physics
2 answers:
tatuchka [14]2 years ago
6 0

Answer:

acceleration = 0.2625 m/s²

Explanation:

   acceleration = ( final velocity - initial velocity ) / time

Here the final velocity is  10.6 m/s and initial velocity is 6.4 m/s and time is 16 s.

using the equation:

acceleration =  ( 10.6 - 6.4 ) / 16

                     = 0.2625 m/s²

Helga [31]2 years ago
3 0

Answer:

V0= 6.4 m/s\\V1= 10.6 m/s\\t = 16s\\V1 = V0 + a.t\\10.6 - 6.4 = a.16\\a=\frac{4.2}{16} \\a=0,2625 m/s^{2}

Explanation:

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How is the atomic mass of an atom determined?​
Ipatiy [6.2K]

Answer:

Atomic mass is defined as the number of protons and neutrons in an atom

5 0
2 years ago
A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0055 m/s2 less than that at sea leve
pshichka [43]
Gs*rs^2 = gm*rm^2 
<span>rm = rs*√gs/gm </span>
<span>rm = 6370*√9.83/(9.83-0.009) = 6372.92 </span>
<span>mountain observatory is placed at an altitude worth 2920 m asl

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7 0
3 years ago
MATHPHYSSSSSSSS PLEASEEEEEE IM SORRY YOU PROBABLY HATE ME
inysia [295]

Answer:

3.1 m/s

Explanation:

First, find the time it takes for the cat to land.  Take down to be positive.

Given:

Δy = 0.61 m

v₀ = 0 m/s

a = 9.81 m/s²

Find: t

Δy = v₀ t + ½ at²

(0.61 m) = (0 m/s) t + ½ (9.81 m/s²) t²

t = 0.353 s

Now find the horizontal velocity needed to travel 1.1 m in that time.

Given:

Δx = 1.1 m

a = 0 m/s²

t = 0.353 s

Find: v₀

Δx = v₀ t + ½ at²

(1.1 m) = v₀ (0.353 s) + ½ (0 m/s²) (0.353 s)²

v₀ = 3.1 m/s

3 0
2 years ago
A 25 kg child is riding on a swing. If the child travels 8.9 m/s at the bottom of their swing, how high into the air is the chil
Setler [38]

Answer:

h = 4.04 m

Explanation:

Given that,

Mass of a child, m = 25 kg

The speed of the child at the bottom of the swing is 8.9 m/s

We need to find the height in the air is the child is able to swing. Let the height is h. Using the conservation of energy such that,

mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}

Put all the values,

h=\dfrac{(8.9)^2}{2\times 9.8}\\\\h=4.04\ m

So, the child is able to go at a height of 4.04 m.

7 0
2 years ago
A standing wave is created on a string of length 1.2 m. If the speed of the wave on the string is 60.0 m/s, what is the fundamen
coldgirl [10]

Answer:

Fundamental frequency in the string will be 25 Hz

Explanation:

We have given length of the string L = 1.2 m

Speed of the wave on the string v = 60 m/sec

We have to find the fundamental frequency

Fundamental frequency in the string is equal to f=\frac{v}{2L}, here v is velocity on the string and L is the length of the string

So frequency will be equal to f=\frac{v}{2L}=\frac{60}{2\times 1.2}=25Hz

So fundamental frequency will be 25 Hz

6 0
3 years ago
Read 2 more answers
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