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mojhsa [17]
3 years ago
5

Which table can be created using the equation below? –2 + 4x = y Answers are below.

Mathematics
2 answers:
Nikitich [7]3 years ago
5 0
If you want you can rewrite the formula into slope intercept form so you don't get confused:
y=4x-2
Choice 1:
y=4x-2
y=4(-5)-2
y=-20-2
y=-22

y=4(0)-2
y=0-2
y=-2

y=4(3)-2
y=12-2
y=10

The best choice is the first one.
I hope this helped!
poizon [28]3 years ago
4 0

Answer:

Option 1 .

Step-by-step explanation:

The given equation is y=4x-2.

when x= -5 ,

y=4(-5)-2

y=-22.

When x=0 ,

Then y=4(0)-2.

y=-2.

When x=3,

y=4(3)-2.

y=10.

When x=-22.

y=4(-22) -2

y=-90

Among all the given options the  first table is the right answer.

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What are the potential solutions of In(x2 - 25) = 0?
Paha777 [63]

Answer:

x=\pm\sqrt{26}

Step-by-step explanation:

ln(x^2-25)=0

e^{ln(x^2-25)}=e^0

x^2-25=1

x^2=26

x=\pm\sqrt{26}

7 0
3 years ago
The bases of a right prism are isosceles trapezoids with bases of 10 ft and 18 ft
likoan [24]

Answer:

540 ft^2.

Step-by-step explanation:

The area of the trapezoid = h/2 (10 + 18) = 14h.

By Pythagoras the height h = √(5^2 - 4^2) = 3.

So the area of the 2 trapezoidal bases = 2 * 14*3

= 84 ft^2.

Now we calculate the area of the four lateral rectangular sides:

= 10*12 + 18*12 + 2*5*12

= 456 ft^2.

Total area =  456 + 54

= 540 ft^2.

4 0
3 years ago
If guy walks from his house to school and back,how far does he walk?
Serga [27]
He walked the same distance to school and back home.
I hope this helped! :-)
8 0
3 years ago
Read 2 more answers
Geometry question need help finding the answers to this
Oksi-84 [34.3K]

Answer:

L' (-1, 1)

M' (1, 2)

N' (1, -1)

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%20%2B11x%2B2%3D0" id="TexFormula1" title="5x^{2} +11x+2=0" alt="5x^{2} +11x+2=0"
eimsori [14]

The solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the solution to the quadratic equation?</h3>

A quadratic equations can be split to several equations and it can be solved as a whole

In this case, the quadratic equation is given as

5x^2 + 11x + 2 = 0

Using the form of the quadratic equation y = ax^2 + bx + c, we have

a = 5, b = 11 and c = 2

The quadratic equation can be solved using the following formula

x = (-b ± √(b^2 - 4ac))/2a

Substitute the known values of a, b and c in the above equation

x = (-11 ± √(11^2 - 4 * 5 * 2))/2*2

Evaluate the exponent

x = (-11 ± √(121 - 4 * 5 * 2))/2*2

Evaluate the products

x = (-11 ± √(121 - 40))/4

Evaluate the sum

x = (-11 ± √(81))/4

Take the square root of 81

x = (-11 ± 9)/4

Expand

x = 1/4 * (-11 + 9) or x = 1/4 * (-11 - 9)

Evaluate the difference

x = 1/4 * -2 or x = 1/4 * -20

Evaluate the product

x = -1/2 or x = -5

Hence, the solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

4 0
2 years ago
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