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Vadim26 [7]
4 years ago
8

Explain how methane (ch4) and ethane (c2h6) demonstrate the law of definite composition and the law of multiple proportions

Chemistry
2 answers:
andrezito [222]4 years ago
7 0

Law of definite composition: The elements which are present in the compound is combined in the same proportion by mass.

Law of multiple proportion: When two or more compounds are formed by the combination of two elements then the mass ratio of one element is combined with the fixed mass of the other element.

In case of methane, it consist of one carbon atoms and four hydrogen atoms implies that has definite composition. In terms of mass, in methane, carbon and hydrogen atoms are combined in a definite ratio i.e. 12 g C/ 4 g H. Thus, methane has definite composition.  

Now, carbon and hydrogen combines to give a class i.e. hydrocarbon. In this case, for every constant mass of carbon the ratio of hydrogen will always reduce to 4/3 ratio for the formation of ethane (hydrocarbon). Thus, law of multiple proportion followed.

Similarly, in case of ethane, this compound also consist of exact atoms but in different ratios.

In case of ethane, it consist of two carbon atoms and six hydrogen atoms implies that has definite composition. In terms of mass, in ethane, carbon and hydrogen atoms are combined in a definite ratio i.e. 24 g C/ 6 g H. Thus, methane has definite composition.  

Now, carbon and hydrogen combines to give a class i.e. hydrocarbon. In this case, for every constant mass of carbon the ratio of hydrogen will always reduce to a specific ratio for the formation of methane (hydrocarbon). Thus, law of multiple proportion followed.


liubo4ka [24]4 years ago
4 0

Methane and ethane demonstrate the law of definite composition and the law of multiple proportions as these both compounds have the exact atoms but in different ratios.  

As for methane, it can be seen that every methane molecule contains 4 hydrogen atoms and 1 carbon atom. Where masses of carbon and hydrogen are in ratio - 12 g C / 4 g H -- reduce to 3g C/ 1 g H .

Ethane contains 2 carbon atoms and 6 hydrogen atom and their mass ratio will be  - 24 g C / 6 g H -- reduce to 4 g C/ 1 g H .

So both ethane and methane demonstrate the law of definite composition and the law of multiple proportions.

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lorasvet [3.4K]

Answer:

neutral idk

Explanation:

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4 years ago
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How many isomers are there in C7H16 ?<br><br>a. 6<br>b. 7<br>c. 8<br>d. 9​
Mariulka [41]
The correct answer is 9 .
7 0
3 years ago
At a particular temperature, the solubility of Kr in water is 0.060 M when the partial pressure is 0.90 atm. What partial pressu
elena55 [62]

At a particular temperature, the solubility of He in water is 0.060 M when the partial pressure is 0.90 atm. 2.27 atm is the partial pressure of Kr would give a solubility of 0.150 M.

<h3>What is Henry's Law ?</h3>
  • According to Henry's law, the weight of a gas dissolved by a liquid is proportional to the pressure of the gas onto the liquid.
  • With very few exceptions, a solute molecule in an extremely diluted solution will only have solvent molecules as its close neighbors. This means that the likelihood that a specific solute molecule will escape into the gas phase is predicted to be independent of the total concentration of solute molecules.

Solution:

The solubility of gas is directly proportional to partial pressure. It is expressed as:

S = K_ h \times P _g_a_s

where, S = Solubility of gas

K_h = Henry's Law constant

P_g_a_s = Partial pressure of gas

Now, put the values in above expression we get

0.060M = K_h × 0.9 atm

   K_h =  = 0.066 M/atm

Now we have to find the partial pressure of He

0.150 M = 0.066 M/atm × P_g_a_s

P_g_a_s = 2.27 atm

Learn more about the Henry's Law : brainly.com/question/23204201

#SPJ4

3 0
2 years ago
Question 4 (1 point)<br> If you have exactly one million atoms how many moles do you have?
rjkz [21]

Answer:

                       1.66 × 10⁻¹⁸  Moles

Explanation:

                     As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Atoms and Avogadro's Number is given as,

             Number of Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms/mol

Putting values,

              Number of Moles  =  1.0 × 10⁶ Atoms ÷ 6.022 × 10²³ Atoms/mol

              Number of Moles  =  1.66 × 10⁻¹⁸  Moles

7 0
4 years ago
1. When _____ <br> are added or removed from an atom, _____<br> is formed
Kobotan [32]

Answer:

1.) protons or electrons 2.) ion

Explanation:

4 0
3 years ago
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