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cupoosta [38]
3 years ago
15

how many grams of calcium chloride arw produced from 10 grams of calcium oxide reacting wity an excessnof hydrochloric acid. CaO

+2Hi=CaCi2+H2o
Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
4 0

CaCO3 is the reactant in excess. The amount of CaCO3 remaining is 11.5 g . ... Hydrochloric acid and calcium chloride. 2 mol HCl1 CaCl2. Determine the mass of CaCO3 that reacted with the limiting reactant HCl .

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Find the reagent to sythesize 1- phenyl-1-propanol
vova2212 [387]

Answer:

aqueous acid is used as a reagent.  

Explanation:

Addition of Grignard reagent in aldehyde and followed by the acidification give rise to the primary or secondary alcohol. when the formaldehyde is used than the primary alcohol is formed otherwise secondary alcohol is formed.

in this reaction we also use the aqueous acid for the acidification as a reagent. We add aqueous acid when ethanol is present. This is because ethanol is get converted in the presence of aqueous acid into the chloroethane.  

4 0
3 years ago
Balance the reaction for the combustion of pentane: ?C5H12+?O2→?CO2+?H2O Enter the four coefficients in order, separated by comm
Daniel [21]

Answer:

The four coefficients in order, separated by commas are 1, 8, 5, 6

Explanation:

We count the atoms in order to balance this combustion reaction. In combustion reactions, the products are always water and carbon dioxide.

C₅H₁₂  +  ?O₂→  ?CO₂ + ?H₂O

We have 12 hydrogen in right side and we can balance with 6 in the left side. But the number of oxygen is odd. We add 2 in the  right side, so we have 24 H, and in the product side we add a 12.

As we add 2 in the C₅H₁₂, we have 10 C, so we must add 10 to the CO₂ in the product side.

Let's count the oxygens: 20 from the CO₂ + 12 from the water = 32.

We add 16 in the reactant side. Balanced equation is:

2C₅H₁₂  + 16O₂→  10CO₂ + 12H₂O

We also can divide by /2 in order to have the lowest stoichiometry

C₅H₁₂  + 8O₂→  5CO₂ + 6H₂O

6 0
3 years ago
The equilibrium constant, Kc, for the following reaction is 0.967 at 650 K. 2NH3(g) N2(g) 3H2(g) When a sufficiently large sampl
AlekseyPX

Answer: Concentration of NH_3 in the equilibrium mixture is 0.31 M

Explanation:

Equilibrium concentration of H_2 = 0.729 M

The given balanced equilibrium reaction is,

                 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

Initial conc.            x                0           0

At eqm. conc.     (x-2y) M     (y) M   (3y) M

The expression for equilibrium constant for this reaction will be:

3y = 0.729 M

y = 0.243 M

K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}

Now put all the given values in this expression, we get :

K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

x=0.80

concentration of NH_3 in the equilibrium mixture = 0.80-2\times 0.243=0.31

Thus concentration of NH_3 in the equilibrium mixture is 0.31 M

3 0
3 years ago
Identify the situations that have an unbalanced force
strojnjashka [21]

Answer:

<u>A baseball speeds up as it falls through the air.</u>

<u>A bumper car hit by another car moves off at an angle.</u>

<u>A balloon flies across the room when the air is released.</u>

Explanation:

<em>Let me know if you need any other help</em>

<em />

6 0
3 years ago
Given the two half-cell reactions for copper and iron below
liraira [26]

Answer:

No, i will not use a water pipe consisting of the two metals

Explanation:

Looking at the reduction potential of the both metals, it is clear that an electrochemical cell is set up with iron as the anode and copper as the cathode.

This will make the iron to quickly corrode and eventually destroy the water pipe. It is better to have a set up in which another metal that is higher than iron in the electrochemical series is combined with it.

6 0
3 years ago
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