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2 years ago

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Earths mass is 5.97 x 10^22kg. The mass of Jupiter is 1.9 x 10^26kg. Mars mass is 6.42 x 10^21kg and Mercury’s is 3.3 x 10^22kg.

Which planet of the four has the greatest mass?

1 answer:

soldier1979 [14.2K]2 years ago

5 0

Answer:

jupiter

Step-by-step explanation:

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Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step

navik [9.2K]

Answer:

A

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the place value for 3 in 318,472,008

VikaD [51]

Salutations!

What is the place value for 318,472,008

The number 3 is in the place as hundred million.

In the numeric form, we can write the number as ------

300, 000, 000.

Hope I helped.

6 0

2 years ago

The formulae for kinetic energy is E =-mv2.<br><br> Find the value of E when m= 900 and v=1.3,

RSB [31]

Answer: ΔKE = 760.5 Joules

Step-by-step explanation:

Isnt the formula for ΔKE = 0.5m*v^2???

Im not going to use that formula you gave me, its wrong.

900/2 = 450

1.3^2 = 1.69

450 x 1.69 = 760.5 Jules

This is also the wrong subject btw

8 0

2 years ago

If g(x)=f(1/3x) which statement is true

uysha [10]

Answer:

the graph of g(x) is horizontally stretched by a factor of 3

Step-by-step explanation:

8 0

3 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

2 years ago