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Elden [556K]
3 years ago
8

Math mathnmath is hard and there is no point of public education

Mathematics
1 answer:
evablogger [386]3 years ago
5 0
I thought that to till on saturday my friend was doing school i was with him he had to do some math algebra 2b he needs it to be a mechanical engineer

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The angles of a triangle are 128, 5x+10 and 9x. What is the value of x?
Advocard [28]
Angles in a triangle total 180°

180=128+5x+10+9x
180-128-10=5x+9x
42=14x
x=3
5 0
3 years ago
Read 2 more answers
Evaluate the mean of each data set mentally.<br> 61, 71, 81, 91, 101
goldfiish [28.3K]

Answer:

10

Step-by-step explanation:

they each go by ten

4 0
3 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
Mazyrski [523]

We can use the fact that, for |x|,

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

Notice that

\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}

so that

f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]

f(x)=\displaystyle5\sum_{n=0}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=1}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=0}^\infty(n+1)x^n

By the ratio test, this series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(n+2)x^{n+1}}{(n+1)x^n}\right|=|x|\lim_{n\to\infty}\frac{n+2}{n+1}=|x|

so the series has radius of convergence R=1.

5 0
3 years ago
What is one benefit of privately issued student loans?
Leona [35]

Answer:

they have lower interest rates and can be paid back with a lower out of pocket cost

Step-by-step explanation:

Student loans are issued as a kind of financial aid that assist students in their quest to acquire higher education. Private student loans are offered by the private-sector lenders. The alternative to this is a Federal loan.

Actually, private student loans are issued at a lower interest rate. Option of a fixed or variable interest rate may be offered on privately issued student loans. This offers a lower out of pocket cost, hence the answer.

6 0
3 years ago
What is the least common multiple of 31, 28, and 14?
WINSTONCH [101]

<u>⇨ By prime factorization method:</u>

\begin{array}{r | l}{\sf{2 & {\sf14,28,31} \\\cline{2-2} {\sf2 & {\sf7,14,31 \\\cline{2-2} {\sf7 & {\sf7,7,31 \\\cline{2-2} {\sf31 & {\sf1,1,31 \\\cline{2-2} & {\sf1,1,1\end{array}

{\sf{LCM\: = \:2 \:x\: 2 \:x\: 7 \:x\: 31}}\\\\{\sf{LCM \:= \:868}}\\}\\{\sf{Therefore,}}\\\\{\sf{LCM\:(14,\: 28,\: 31)\: = \:868

{\boxed{\sf{LCM\:=\:868}}

5 0
2 years ago
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