First we will compute the h+k and then multiply the result by 2.
To add polynomials, we add terms whose variables are alike, for example:
we add the coefficients of x^2 together, the coefficients of x together and so on.
Therefore:
h + k = x^2 + 1 + x - 2 = x^2+x-1
Now, we will multiply this answer by 2 to get the final answer:
2(h+k) = 2(x^2+x-1) = 2x^2 + 2x -2
Answer:
A+6+A = 20
A = 7
Step-by-step explanation:
J = number of problems Juana completed
A = number of problems Andy completed
J+A=20
J = A + 6
Replace J with A+6 in the first equation
A+6+A = 20
2A +6 = 20
Subtract 6 from each side
2A +6-6 = 20-6
2A =14
Divide by 2
2A/2 = 14/2
A = 7
There is a 20 percent chance of choosing a number that would fit the requirements of both a and b this si because only 1 and three are odd and less than three so 2/10 is twenty percent
The graph will cross at the coordinates (-2, 9)
<h3>How to solve equations?</h3>
y = 3x + 15
y = 3 - 3x
y = 3x + 15
Hence,
when x = 2
y = 3(2) + 15 = 21
when x = 0
y = 3(0) + 15 = 15
y = 3 - 3x
when x = 2
y = 3 - 3(2)
y = 3 - 6
y = -3
when x = 0
y = 3 - 3(0)
y = 3
Therefore, let's check if the equation will cross.
y = 3x + 15
y = 3 - 3x
using substitution,
3 - 3x = 3x + 15
3 - 15 = 3x + 3x
- 12 = 6x
x = -12 / 6
x = -2
y = 3 - 3(-2)
y = 3 + 6
y = 9
Therefore, the graph will cross at the coordinates (-2, 9)
learn more on equations here: brainly.com/question/19297665
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(2 5/14) / (2 5/8 * 1 3/7)....turn them all into improper fractions
(33/14) / (21/8 * 10/7)
(33/14) / (105/28)...when dividing fractions, flip what u r dividing by, then multiply
33/14 * 28/105 = 132/210 reduces to 22/35 <==
