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Reptile [31]
4 years ago
6

A company that makes​ hair-care products had 3 comma 000 people try a new shampoo. Of the 3 comma 000 ​people, 12 had a mild all

ergic reaction. What percent of the people had a mild allergic​ reaction?
Mathematics
2 answers:
Allisa [31]4 years ago
4 0

Answer:

0.4%

Step-by-step explanation:

In a company that makes​ hair-care products, if 3,000 people try a new shampoo and 12 people had a mild allergic reaction, the percentage of people that had mild allergic reaction can be expressed as;

Number of people allergic/total people that tried a new shampoo × 100%

= 12/3000×100

= 1200/3000

= 0.4%

This shows that 0.4% of the people had a mild allergic​ reaction

Aleksandr [31]4 years ago
3 0

Answer:

0.4%

Step-by-step explanation:

12/3,000 = 0.4%

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The distance between Franklin City and Williamsville on a map is 3.2 inches. If the scale of the map is 1 inch = 15 miles, how m
Darina [25.2K]

Answer: 48 miles

Step-by-step explanation:

From the question, the distance between Franklin City and Williamsville on a map is 3.2 inches and the scale of the map is 1 inch = 15 miles.

The distance between the cities will be to multiply 3.2 by 15 to get the number of miles since 1 inch = 15 miles. This will be:

= 3.2 × 15 miles.

= 48 miles

The distance between Franklin City and Williamsville is 48 miles.

6 0
3 years ago
Please help! geometry problem 3!
Vilka [71]
Comment
|First of all, the triangles are equal by ASA the way the diagram has been marked.

B and E are both right angles.
Side BC = Side DE
<BCA =< EDA 

So triangle BCA = triangle EDA

Now to the letters.
x = y - 1                 Add 1 to both sides.
x + 1 = y                (1)
3x - 2 = 2y + 1       Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y             Divide by 2
3x/2 - 3/2 = 2y/2
1.5x - 1.5 = y    (2)

Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.

1.5x - 1.5 = x + 1       Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1           Add  1.5 to both sides.
0.5x =  1 + 1.5
0.5x = 2.5                 Divide 0.5 on both sides.
0.5x/0.5 = 2.5/0.5

x = 5

Now we need a y value.
x = y - 1 
5 = y - 1 Add 1 to both sides.
5 + 1 = y - 1 + 1
6 = y 

So the 2 sides and the 2 angles are equal when 
x = 5
y = 6

C Answer <<<<<<



 


4 0
3 years ago
Which expressions are equivalent to 2 (three-fourths x + 7) minus 3 (one-half x minus 5)? Check all that apply.
Mariulka [41]

Answer:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

Step-by-step explanation:

The original expression given in the text is

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)  (1)

And we want to check to what other expressions is equivalent. First of all, we solve it by writing explicitely each term:

\frac{3}{2}x+14-\frac{3}{2}x+15 (2)

Let's verify each of the other expressions separately. For the first one:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

We see that this is equivalent to expression (1), since the first half is identical, while in the second one, the combination "+-" can be simply written as "-", so we get

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)

Which is equivalent to (1).

For the 2nd one:

2(\frac{3}{4}x)+2(7)+3(\frac{1}{2}x)+3(-5)

This is not equivalent. In fact, here we have applied the distributive property to each term: however, the 3rd and 4th term are not correct, because the (3) must be negative (-3), as in the original expression.

If we write it explicitely in fact, we get

\frac{3}{2}x+14+\frac{3}{2}x-15

Which is different from (2).

For the 3rd one:

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

This one is equivalent. In fact, here we have applied the distributive property correctly. By solvign each term we get:

\frac{3}{2}x+14-\frac{3}{2}x+15

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Answer:

Answer is in the attached image.

6 0
2 years ago
An automobile manufacturer is concerned about a possible recall of its best selling four-door sedan. If there was a recall there
goldfiish [28.3K]

Complete question is;

An automobile manufacturer is concerned about a possible recall of its best - selling four-door sedan. If there were a recall, there is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area.

(a) What is the probability that the defect is the brakes or the fueling system if the probability of defects in both systems simultaneously is 0.15?

(b) What is the probability that there are no defects in either the brakes or the fueling system?

Answer:

A) 0.27

B) 0.73

Step-by-step explanation:

Let B denote that there is a defect in the break system

Let T demote that there is a defect in transmission

Let F denote that there is a defect in the fuel system.

Let P denote that there is a defect in some other area.

Now, we are given;

P(B) = 0.25

P(T) = 0.18

P(F) = 0.17

P(O) = 0.40

A) We are given that probability of defects in both brakes and the fueling system simultaneously is 0.15.

Thus, it means; P(B ⋂ F) = 0.15

Now, we want to find the probability that the defect is the brakes or the fueling system. This is expressed as;

P(B ⋃ F) = P(B) + P(F) - P(B ⋂ F)

Plugging in the relevant values to give;

P(B ⋃ F) = 0.25 + 0.17 - 0.15

P(B ⋃ F) = 0.27

B) We want to find the probability that there are no defects in either the brakes or the fueling system.

This is expressed as;

P(B' ⋃ F') = 1 - P(B ⋃ F)

Plugging in relevant value;

P(B' ⋃ F') = 1 - 0.27

P(B' ⋃ F') = 0.73

7 0
3 years ago
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