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nikitadnepr [17]
3 years ago
13

Whats 326482745445-453637+938464846-3845+784657

Mathematics
2 answers:
Burka [1]3 years ago
8 0
327421537466 and yes i did all of this that fast 
lubasha [3.4K]3 years ago
7 0
When you do the first step which would be subtracting the 453637 from 326482745445 you get 3.264822918(x10) to the 11 power. Then you add 938464846 you get 3.274207565(x10) to the 11 power. Then you subtract 3845 from that and get 3.274207528(x10) to the 11 power. Finally you add 784657 and get 3.274215375(x10) to the 11 power. 

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the hypotenuse of a right triangle is 3 cm and one of the legs is 1 cm what is the length of the other leg ?
Afina-wow [57]

Answer:

2\sqrt{2}

Step-by-step explanation:

let the other leg be x

Using Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 1² = 3²

x² + 1 = 9 ( subtract 1 from both sides )

x² = 8 ( take the square root of both sides )

x = \sqrt{8}

  = \sqrt{4(2)}

  = \sqrt{4} × \sqrt{2} = 2\sqrt{2} ← exact value

4 0
3 years ago
#1. WILL REWARD BRAINLIEST
Gemiola [76]

c is the answer for 1'


6 0
3 years ago
Given sec(theta)= 5... find cot(90-theta)
Mumz [18]
\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 }  = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} 
\\
\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6}  
\\

3 0
3 years ago
Simplify this algebraic expression.<br><br> 9k + 7 - K + 4 =
Maksim231197 [3]

Answer:

8k+11

Step-by-step explanation:

Combine like terms

9k-k

7+4

9k-k=8k

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8k+11

6 0
3 years ago
Which choices are equivalent to the fraction below? Check all that apply.
lord [1]

Answer:

A, B, D, E, F

Step-by-step explanation:

48/64 can be simplified into all of them except C

3 0
3 years ago
Read 2 more answers
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