Check if it has the properties of gold.
This uses the concept of freezing point depression. When faced with this issue, we use the following equation:
ΔT = i·Kf·m
which translates in english to:
Change in freezing point = vant hoff factor * molal freezing point depression constant * molality of solution
Because the freezing point depression is a colligative property, it does not depend on the identity of the molecules, just the number of them.
Now, we know that molality will be constant, and Kf will be constant, so our only unknown is "i", or the van't hoff factor.
The van't hoff factor is the number of atoms that dissociate from each individual molecule. The higher the van't hoff factor, the more depressed the freezing point will be.
NaCl will dissociate into Na+ and Cl-, so it has i = 2
CaCl2 will dissociate into Ca2+ and 2 Cl-, so it has i = 3
AlBr3 will dissociate into Al3+ and 3 Br-, so it has i = 4
Therefore, AlBr3 will lower the freezing point of water the most.
Hi, these are the answers:-
Thigh bone → Organ
Living cell → Cell
Bone cells working together→ Tissue
All the bones, cartilages and ligaments→ Organ System
Hope it helps you...
Pls mark brainliest if it helps you...
(Answered by Benjemin)
Answer:
Kp = 0.35 & Kc = 0.0075
Explanation:
PCl₅ ⇄ PCl₃ + Cl₂
Initial(atm) 0.5 0 0
At equilibrium 0.5 - p p p
- Total pressure at equilibrium = 0.78
- 0.5 - p + p + p = 0.78
- p = 0.28
So partial pressure of PCl₅ = 0.5 - 0.28 = 0.22 atm
Similarly PCl₃ = 0.28 atm & Cl₂ = 0.28 atm
According to law of mass action
- Kp =
- Kp =
- Kp = 0.35
We know Kp = Kc x (RT)Δng
Δng = change in gaseous moles
= product moles - reactant moles
= 2 - 1
= 1
R = universal gas constant = 0.0821 lit. atm. mol⁻¹. K⁻¹
So Kc =
= 0.0081
Answer:
True
Explanation:
They have four distinct stages: egg, larva (caterpillar), pupa (chrysalis), and adult. For monarch butterflies, it takes about a month to grow from an egg to an adult.
The life cycle of a frog consists of three stages: egg, larva, and adult.