It has bent geometry, which is similar to H2O, with the same angle of 109.5 degrees between 2 single H-S bonds.
A. Shaman
Shaman were revered as people with the ability to communicate with good and evil spirits and heal ailments.
A decrease in volume w/ temp constant
An increase in temp w/ volume constant
An increase in the amount of gas w/ temp & volume constant
Answer:
(a) 0.22 mol Cl₂ and 15.4g Cl₂
(b) 2.89.10⁻³ mol O₂ and 0.092g O₂
(c) 8 mol NaNO₃ and 680g NaNO₃
(d) 1,666 mol CO₂ and 73,333 g CO₂
(e) 18.87 CuCO₃ and 2,330g CuCO₃
Explanation:
In most stoichiometry problems there are a few steps that we always need to follow.
- Step 1: Write the balanced equation
- Step 2: Establish the theoretical relationship between the kind of information we have and the one we are looking for. Those relationships can be found in the balanced equation.
- Step 3: Apply conversion factor/s to the data provided in the task based on the relationships we found in the previous step.
(a)
Step 1:
2 Na + Cl₂ ⇄ 2 NaCl
Step 2:
In the balanced equation there are 2 moles of Na, thus 2 x 23g = 46g of Na. <u>46g of Na react with 1 mol of Cl₂</u>. Since the molar mass of Cl₂ is 71g/mol, then <u>46g of Na react with 71g of Cl₂</u>.
Step 3:
(b)
Step 1:
HgO ⇄ Hg + 0.5 O₂
Step 2:
<u>216.5g of HgO</u> form <u>0.5 moles of O₂</u>. <u>216.5g of HgO</u> form <u>16g of O₂</u>.
Step 3:
(c)
Step 1:
NaNO₃ ⇄ NaNO₂ + 0.5 O₂
Step 2:
<u>16g of O₂</u> come from <u>1 mol of NaNO₃</u>. <u>16g of O₂</u> come from <u>85g of NaNO₃</u>.
Step 3:
(d)
Step 1:
C + O₂ ⇄ CO₂
Step 2:
<u>12 g of C</u> form <u>1 mol of CO₂</u>. <u>12 g of C</u> form <u>44g of CO₂</u>.
Step 3:
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(e)
Step 1:
CuCO₃ ⇄ CuO + CO₂
Step 2:
<u>79.5g of CuO</u> come from <u>1 mol of CuCO₃</u>. <u>79.5g of CuO</u> come from <u>123.5g of CuCO₃</u>.
Step 3:
Answer:
A = B < D < C
C - S
Cl - Cl
F ← H
Si → O
Explanation:
The polarity of a bond increases with the increase in the difference in electronegativity. The dipole moment is represented with an arrow pointing the more electronegative atom.
A: carbon-sulfur
C - S
ΔEN = |EN(C) - EN(S)| = |2.5 - 2.5| = 0
B: chlorine - chlorine
Cl - Cl
ΔEN = |EN(Cl) - EN(Cl)| = |3.0 - 3.0| = 0
C: fluorine – hydrogen
F ← H
ΔEN = |EN(F) - EN(H)| = |4.0 - 2.1| = 1.9
D: silicon - oxygen
Si → O
ΔEN = |EN(Si) - EN(O)| = |1.8 - 3.5| = 1.7
The order of increasing polarity is A = B < D < C.