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kodGreya [7K]
3 years ago
14

For two variables in a direct proportion, what is the result of doubling one variable? the other variable is doubled the other v

ariable is halved the other variable stays constant
Chemistry
2 answers:
Aliun [14]3 years ago
8 0
Other variable is doubled.
murzikaleks [220]3 years ago
6 0

the other variable is doubled.

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What type of compound is B4F10, and what is its name?​
Gemiola [76]

A binary compound is a compound formed from two different elements. There may or may not be more than one of each element. A diatomic compound (or diatomic molecule) contains two atoms, which may or may not be the same.

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Nomenclature of Ionic and Covalent Compounds.

4 0
2 years ago
What are the products of the following combustion reaction?<br><br> 2C2H2(g) + 5O2(g) →
kakasveta [241]
A combustion reaction of an  will generally produce CO2 and H20 -- carbon dioxide and water and/or an oxide

looking at the combustion material C2H2, you know that the end products will be CO2 and H20, so the question is how much of each will you get

well, look at the total amount of carbon atoms, 2 C2, which means a total of 4 carbon atoms in this reaction, since only CO2 has carbon atoms, that means there must be 4 CO2 as an end product and 4 CO2 will use up 4 of 5 O2 molecule leaving only 1 O2 molecule for the H2 reaction.

now O2 has a total of 2 oxygen molecules whereas H20 has only a single oxygen molecule, hence the end product must have 2 H20

check that the H atoms balance out on both sides
4 0
3 years ago
Read 2 more answers
A 2.950×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in w
11111nata11111 [884]

Answer:

The molality of the glycerol solution is 2.960×10^-2 mol/kg

Explanation:

Number of moles of glycerol = Molarity × volume of solution = 2.950×10^-2 M × 1 L = 2.950×10^-2 moles

Mass of water = density × volume = 0.9982 g/mL × 998.7 mL = 996.90 g = 996.90/1000 = 0.9969 kg

Molality = number of moles of glycerol/mass of water in kg = 2.950×10^-2/0.9969 = 2.960×10^-2 mol/kg

7 0
4 years ago
There are ________ mol of bromide ions in 0.700 L of a 0.400 M solution of AlBr
denis23 [38]

Answer:

The number of moles of AlBr3 = Molarity × Volume

= 0.400 × 0.700

= 0.28 moles

1 mole of AlBr3 gives 3 moles of Br- ions

That is

AlBr3 = Al3+ + 3Br-

Therefore, 0.045 moles of AlBr3 will yield 3 × 0.28 = 0.84 moles

Thus; they are 0.84 moles of bromide ions

5 0
2 years ago
Which of the following gases would have the greatest volume at STP?. A. 5.00 moles of H2 gas. B. 5.00 g of Rn gas. C. 6.02 × 102
Rudik [331]
To determine the answer above, assume that the gases behave as ideal and that we only need to compare the number of moles.
For letter A. there are 5 moles of H2 gas.
For letter B, convert the amount in gas to moles by dividing it by 222 g/mol. This gives an answer of 0.0225 moles
For letter C, the given amount is Avogadro's number which corresponds to 1 mole.

Thus, the answer is letter A.
4 0
4 years ago
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