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disa [49]
3 years ago
9

When a scientist conducts an investigation, which of the following is the first thing he or she should do?

Chemistry
2 answers:
Vinvika [58]3 years ago
6 0

The correct answer is C

Lelu [443]3 years ago
5 0
The correct answer is "B. Make a Hypothesis".
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Lionel places red blood cells in a beaker of pure water, and then he observes their
scZoUnD [109]

Answer:

The red blood cells will burst

Explanation:

When the red blood cells are placed in pure water, they will gain water by osmosis, swell and finally burst due to their weak cell membranes. This process is referred to as hemolysis.

7 0
3 years ago
How many moles in 44.7 kg of carbon dioxide
slava [35]

Answer:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

Explanation:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

7 0
2 years ago
The [Fe(H₂O)₆]³⁺ complex requires a relatively small amount of energy to promote an electron from the t2g to the eg. Based on th
Olin [163]

Answer:

The spin of the complex is 5.92 B.M

Explanation:

Please see the attachments below

4 0
3 years ago
How many atoms are in 187.6 grams of the alloy?
Ad libitum [116K]
13 Al Aluminum Atomic mass 26.982
8 0
3 years ago
Read 2 more answers
How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g

5 0
3 years ago
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