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Serggg [28]
3 years ago
15

How do acids and bases affect molecules such Proteins? ​

Chemistry
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

Strong acids and bases both denature proteins by severing disulphide bonds and at higher temperatures, can break proteins into peptides, or even individual amino acids.

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Elaborate what knowing that carbon-14 has an atomic number of 6 tells us about the atom
erma4kov [3.2K]

Answer:

This information tells us that carbon-14 is an isotope of carbon-12. Isotopes are atoms with the same atomic number but different mass number. The Atomic number is the number of protons in the nucleus of an atom. The Mass number is the total number of protons and neutrons in an atomic nucleus. Both carbon-14 and carbon-12 have 6 protons, 6 electrons, but they differ in the fact that carbon-14 has 8 neutrons as opposed to 6 neutrons in carbon-12.

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3 years ago
7. Which of the following elements is diatomic?
Hunter-Best [27]

Answer:

7. is F

8. they are all linear and have the length or distance between two atoms

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3 years ago
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List the metals and non metals in CBr4
goldfiish [28.3K]

Answer:

Metals: Carbon,

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3 years ago
A chemist adds of a iron(III) bromide solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the che
vaieri [72.5K]

Answer:

0.246 kg

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist adds 370.0mL of a 2.25 M iron(III) bromide (FeBr₃) solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>

<em />

We have 370.0 mL of 2.25 M iron(III) bromide (FeBr₃) solution. The moles of FeBr₃ are:

0.3700 L × 2.25 mol/L = 0.833 mol

The molar mass of iron(III) bromide is 295.56 g/mol. The mass corresponding to 0.833 moles is:

0.833 mol × 295.56 g/mol = 246 g

1 kilogram is equal to 1000 grams. Then,

246 g × (1 kg/1000 g) = 0.246 kg

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4 years ago
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Studentka2010 [4]

Explanation:

Set up the ion formation equations, with ionization energy values for each electron in the valence layer, of the atoms of the chemical elements below: a) Na z=11 b) Ca z= 20 c) Sr z 38 d) Li z= 3 e) Cs z= 55 f) Be z= 43

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3 years ago
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