The concentration of iron in ppb is 5.2 ppb
In atmospheric chemistry, PPM( parts per million) and PPB( parts per billion) units are used to express the concentration of gases. PPB stands for parts per billion, while PPM stands for parts of gas per million parts of air.
2.6 × 10⁻⁶ grams of iron in 500 ml of water.
Now, converting milliliter into liter:
500 mL = 500 mL × ( 1L / 1000 mL ) = 0.5 L
Now for ppm, mass must be in mg.
2.6 × 10⁻⁶ grams = 2.6 × 10⁻⁶ grams × ( 1000 mg / 1 grams ) = 2.6 × 10⁻³ mg
Then, the concentration of iron in ppm will be:
2.6 × 10⁻³ mg / 0.5 L = 5.2 × 10⁻³ ppm
Now, 1 ppm = 1000 ppb
Therefore,
5.2 × 10⁻³ ppm × 10³ = 5.2 ppb
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This is false because it doesn't matter about the mass
Answer:
the answer is b hope it helped
Explanation:
Answer:
378mL
Explanation:
The following data were obtained from the question:
Pressure (P) = 99.19 kPa
Temperature (T) = 28°C
Number of mole (n) = 0.015 mole
Volume (V) =...?
Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:
For Pressure:
101.325 KPa = 1 atm
Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm
For Temperature:
T(K) = T(°C) + 273
T(°C) = 28°C
T(K) = 28°C + 273 = 301K.
Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:
PV = nRT
Pressure (P) = 0.98 atm
Temperature (T) = 301K
Number of mole (n) = 0.015 mole
Gas constant (R) = 0.0821atm.L/Kmol.
Volume (V) =...?
0.98 x V = 0.015 x 0.0821 x 301
Divide both side by 0.98
V = (0.015 x 0.0821 x 301) /0.98
V = 0.378 L
Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:
1L = 1000mL
Therefore, 0.378L = 0.378 x 1000 = 378mL
Therefore, the volume of N2 collected is 378mL
