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Katarina [22]
3 years ago
14

A supermarket finds that the number of boxes of a new cereal sold increases each week. In the first week, only 26 boxes of the c

ereal were sold. In the next week, 57 boxes of the cereal were sold and in the third week 88 boxes of the cereal were sold. The number of boxes of cereal sold each week represents an arithmetic sequence. What is the explicit rule for the arithmetic sequence that defines the number of boxes of cereal sold in week n?
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

If the pattern goes 26, 57, 88 you can find the difference between each number to see how much it's going up by each time. 57 - 26 = 31 and 88 - 57 = 31

That means each week the number of boxes of a new cereal increases by 31, or +31

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A shoe store marks up is merchandise by 8%. what was the selling price of a shoe whose whole price is $24.50?
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What is the discrimination of the quadratic equation 6x^2-9x-8=0
aleksklad [387]

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6 0
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Please help, i'm horrible @ math :)
katovenus [111]
   
\displaystyle\\
1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\  \\ 
1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\  \\ 
-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\  \\ \texttt{OR} \\  \\ 
-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }


\displaystyle\\
\Longrightarrow ~~1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) =\frac{7}{5} -\frac{11}{2} = \frac{7\times 2}{5\times 2} -\frac{11\times 5}{2\times 5} = \\  \\ 
= \frac{14}{10} -\frac{55}{10} = \frac{14-55}{10} =\frac{-41}{10} = -\frac{41}{10}=-\frac{40+1}{10}=\boxed{\boxed{-4\frac{1}{10}}}



7 0
3 years ago
A random sample of 225 individuals working in a large city indicated that 45 are dissatisfied with their working conditions. Bas
Lorico [155]

Answer:

CI 90 %  =  [  0,165  ;  0,235 ]

Lower limit     0,165

upper limit      0,235

Step-by-step explanation:

Sample information:

sample size    n  =  225

number of dissatisfied  individuals   x  =  45

p = 45/225

p = 0,2    and  q =  1 -  p   q  =  1  -  0,2   q  =  0,8

p*n = 0,2*225   =  45    and   q*n   =  0,8*225  =  180

p*n  and q*n  big enough to use the approximation of binomial distribution to normal distribution

90 % of Confidence Interval   then a significance level is  α  = 10%

α  =  0,1 in z table we get z(c) for that significance level

z(c) = 1,28

CI 90 %   =  [  p  ±  z(c)*√(p*q)/n ]

z(c) * √(p*q)/n    =  1,28 *  √ ( 0,2*0,8)/225

z(c) * √(p*q)/n    =  1,28 * 0,027

z(c) * √(p*q)/n    =  0,035

CI 90 %  =  [  0,2  ±  0,035 ]

CI 90 %  =  [  0,165  ;  0,235 ]

Lower limit     0,165

upper limit      0,235

3 0
3 years ago
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andrew-mc [135]
X = -2 is the answer
7 0
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