Ask question

Ask question

All categories

4 years ago

6

Maya wants to buy a piano. The piano measures 19/4 feet long. She has a space 5 feet long for the piano in her house. Does she h

ave enough room? Draw a number line and explain your answer.

1 answer:

Sophie [7]4 years ago

8 0

Yes, 19/4 is only 4/3/4 so you still have 1/4 ft left to fill

You might be interested in

Besides 26 and 1, what is one factor of 26?

Ainat [17]

13 and 2, I think that is the only one left.

5 0

3 years ago

Read 2 more answers

Factor -24a3b3c3 - 84a4b2c.

sammy [17]

Answer:

-12a³b²c ( 2bc² + 7a)

Step-by-step explanation:

To factorize, we must separate the highest common factors between the products that make up the given expression. To get the highest common factor between the two products,

-24a3b3c3 = -2 * 2 *2 * 3 * a³ *b² *b * c² * c

- 84a4b2c = -2 * 2 *3 * 7 * a³ * a *b² * c

The common elements are -2, 2, 3, a³, b², c

The product of the common elements

= -12a³b²c

Hence, factorizing

-24a3b3c3 - 84a4b2c = -12a³b²c ( 2bc² + 7a)

4 0

3 years ago

Read 2 more answers

2. Evan solved the equation above. He ended up with an improper fraction as his product. Help Evan convert his improper fraction

Goryan [66]

I think it would be like how many times does 5 go into 48.. and that would be 9 and 3/5

4 0

3 years ago

If the cos of angle x is 8 over 17 and the triangle was dilated to be two times as big as the original, what would be the value

Viktor [21]

Answer:

the answer is 8/17

Step-by-step explanation:

i got it right on the quiz

6 0

3 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago