Answer: alkaline earth metals (group-IIA)
Explanation:
The element which donates the electron is known as electropositive element and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element and forms a negatively charged ion called as anion.
Alkaline earth metals donate 2 valence electrons to acquire noble gas configuration.
For example: Berrylium is the first alkaline earth metal with atomic number of 4 and thus has 4 electrons
Electronic configuration of berrylium:
![[Be]:4:1s^22s^2](https://tex.z-dn.net/?f=%5BBe%5D%3A4%3A1s%5E22s%5E2)
Berrylium atom will loose two electrons to gain noble gas configuration and form berrylium cation with +2 charge.
![[Be^{2+}]:2:1s^2](https://tex.z-dn.net/?f=%5BBe%5E%7B2%2B%7D%5D%3A2%3A1s%5E2)
Thus Elements donate 2 electron to produce a cation with a 2+ charge are alkaline earth metals.
Answer:
0.22 mol HClO, 0.11mol HBr.
0.25mol NH₄Cl, 0.12 mol HCl
Explanation:
A buffer is defined as a mixture in solution between weak acid and its conjugate base or vice versa.
Potassium hypochlorite (KClO) could be seen as conjugate base of HClO (Weak acid). That means the addition of <em>0.22 mol HClO </em>will convert the solution in a buffer. HBr reacts with KClO producing HClO, thus, <em>0.11mol HBr</em> will, also, convert the solution in a buffer. 0.23 mol HBr will react completely with KClO and in the solution you will have only HClO, no a buffering system.
Ammonia (NH₃) is a weak base and its conjugate base is NH₄⁺. That means the addition of <em>0.25mol NH₄Cl</em> will convert the solution in a buffer. Also, NH₃ reacts with HCl producing NH₄⁺. Thus, addition of<em> 0.12 mol HCl</em> will produce NH₄⁺. 0.25mol HCl consume all NH₃.
From the equation of the graph, the activation energy of the reaction is -2.2 * 10⁴ J/mol.
<h3>What is activation energy?</h3>
Activation energy is the minimum required energy that reactant molecules must possess for a reaction to proceed towards formation of products.
The activation energy is determined from the slope of ln k against 1/T(K).
Given the equation, y = -2.2 * 10⁴ x + 45.0.
Comparing with the equation of a straight line, y = mx + c
The gradient, m = -2.2 * 10⁴
Therefore, the activation energy of the reaction is -2.2 * 10⁴ J/mol.
In conclusion, reactant molecules must break the activation energy barrier in order to form products.
Learn more about activation energy at: brainly.com/question/26724488
#SPJ1
The δs∘rxn for the reaction 
→ 
will be -146 J/K.
Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.
Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit 
.
Entropy of the reaction can be calculated by the reaction.
Δ
= 2 mol × 
× 
- 1 mol × 
Δ = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol ×205.2 J/mol.K
Δ = -146.8 J/K
Therefore, the δs∘rxn for the reaction → will be -146 J/K.
To know more about reaction
brainly.com/question/20305735
#SPJ4
Answer:
I
Explanation:
don't know anything sorry for inconvenience
