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Answer : The heat of the reaction is, 1.27 kJ/mole
Explanation :
First we have to calculate the heat released.
Formula used :
or,
where,
Q = heat = ?
m = mass of sample = 1.50 g
c = specific heat of water = 
= initial temperature = 
= final temperature = 
Now put all the given value in the above formula, we get:
Now we have to calculate the heat of the reaction in kJ/mol.
where,
= enthalpy change = ?
Q = heat released = 0.0238 kJ
n = number of moles NH₄NO₃ = 
Therefore, the heat of the reaction is, 1.27 kJ/mole
We are given the balanced equation 2NaF + Ca10(PO4)6(OH)2 → Ca10(PO4)6F2 + 2NaOH. The fluorapatite is the product together with sodium hydroxide. The ions involved are (PO4) 3-, Ca 2+ and <span>F-. We add the charges and check if the sum is zero, 2*10+-3*6+-1*2 =0. the zero sum tells that the compound has zero charge or neutral</span>
Answer:
HBr + Mg(OH)2 —> MgBr2 + H2O.
To balance the above, we must do a head count of the individual atoms present to ensure they balance on both sides of the equation. To get the balance equation, add 2 in front of HBr and 2 in front of H2O as shown below:
2HBr + Mg(OH)2 —> MgBr2 + 2H2O
We can see clearly that the numbers of the individual atoms on the left side is the same on the right side
