Answer:
0.542M HCl
Explanation:
The reaction of H₂SO₄ with NaOH is:
H₂SO₄ + 2 NaOH → 2H₂O + Na₂SO₄
<em>Where 1 mole of acid reacts with 2 moles of NaOH</em>
Moles of H₂SO₄ are:
0.0500L × (0.361mol / L) = 0.01805 moles H₂SO₄
Thus, moles of NaOH that neutralize this acid are:
0.01805 moles H₂SO₄ × (2 mol NaOH / 1 mol H₂SO₄) = 0.0361 moles NaOH
And concentration is:
0.0361 moles NaOH / 0.0200L = <em>1.805M</em>
And, reaction of NaOH with HCl is:
NaOH + HCl → H₂O + NaCl
<em>Where 1 mole of NaOH reacts per mole of NaOH</em>
As you use 30.0mL = 0.0300L of NaOH to neutralize the HCl acid, moles of acid are:
0.0300L × (1.805mol / L) = 0.05415 moles NaOH = moles HCl
In 0.1000L:
0.05415 moles HCl / 0.1000L = <em>0.542M HCl</em>
The answer to your question is aluminum.
Answer:
12
Explanation:
pOH = -log(1.0 x 10^-2) = 2
pH = 14 - pOH
pH = 14 - 2 = 12
<span>Cleavage because the thin sheets will break apart easily in one direction but not the other.</span>
Answer:
0.082 M
Explanation:
First we calculate the moles of KOH added, by multiplying its volume and concentration:
- 0.22 M * 16 mL = 3.52 mmol KOH
Given that <em>one mole of acid reacts with one mole of base</em>, in the lactic acid sample there were 3.52 acid moles as well.
Finally we divide the acid moles by the volume, to calculate the concentration:
- 3.52 acid moles / 43 mL = 0.082 M