It's a physical property because it doesn't change the element of the metal.
does this make sense?
Answer:
The correct answer will be "
".
Explanation:
We have:
Moles of solute (Na₂Co₃) = 
= 
= 
Now,
The volume of the solution will be:
⇒ 
∴ 
The formula to find the concentration will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
CH4 + O2 = CO2 + H2O - Chemical Equation Balancer.
The neutralization reaction between potassium hydroxide and sulfuric acid is as follows
2KOH + H2SO4 ---> K2SO4 + 2H2O
number of moles of KOH= (43.74 x 0.500)/ 1000= 0.02187 moles
the reacting ratio of KOH to H2SO4 is 2:1 therefore the moles of H2SO4 is = 0.021187/2= 0.01094 moles
concentration(molarity) = ( 0.01094/50 ) x 1000= 0.2188M