The volume of a 6.67 m nacl solution
that contains 3.12 mol nacl is 0.468.
You just need to follow this formula:
C = n / V
So, it will be
V = n / C
<span> = 3.12 / 6.67 moles / Liter </span>
<span> = 0.468 L</span>
Answer: The pressure will be 18.05 atm.
Explanation: Expression for ideal gas equation is :

where,
P = Pressure of the gas = ? atm
V = Volume of the gas = 0.333L
n = Number of moles of gas = 0.250 moles
R = Universal gas constant = 
T = temperature of the gas = 20°C = (273 + 20)K = 293K
Putting values in above equation, we get:

P = 18.05 atm
Moles are an estimation of the smallest unit of the molecules and the atoms in a sample. The moles of ammonium nitrate in a sample are 0.5010 moles.
<h3>What are moles?</h3>
Moles are calculated by dividing the mass of the substance in gm by that of the molar mass in gram per mole.
Given.
Mass of ammonium nitrate = 40.10 gm
The molar mass of ammonium nitrate = 80. 0432 g/mol
Moles of ammonium nitrate are calculated as:

Therefore, moles of ammonium nitrate present is option d. 0.5010 moles.
Learn more about moles here:
brainly.com/question/2396149
Answer:
z≅3
Atomic number is 3, So ion is Lithium ion (
)
Explanation:
First of all
v=f*λ
In our case v=c
c=f*λ
λ=c/f
where:
c is the speed of light
f is the frequency

Using Rydberg's Formula:

Where:
R is Rydberg constant=
z is atomic Number
For highest Energy:
n_1=1
n_2=∞

z≅3
Atomic number is 3, So ion is Lithium ion (
)