A 2.45-g sample of strontium completely reacts with oxygen to form 2.89 g of strontium oxide. Use this data to calculate the mas
2 answers:
Answer:
The % Mass Composition of Sr is <em>74.72≅ 75%</em>
Explanation:
The balanced equation:
Sr + O2 → SrO2
Molecular mass of SrO2 = 87.6 + (16 × 2) = 119.6 gmol-1
1 mole SrO2 = 119.6gmol-1
how many mole is in 2.5 g of SrO2 = 2.5÷119.6
= 0.0209 mol
The mole ration of the equation is:
1 mole SrO2 was produced by 1 Sr ion and 1 O2 ion
SrO2: Sr ratio is 1:1
⇒0.0209 mol SrO2 = 0.0209 mole of Sr
mass of Sr = 0.0209 × 87.6gmol-1
= 1.83g
∴ & mass of Sr in sample = × 100
= 74.72≅ 75%
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