Ask question

Ask question

All categories

3 years ago

6

Solve for a 6(a+3)=18+6a

1 answer:

Dominik [7]3 years ago

4 0

Expand

(6a + 18 = 18 + 6a)

Cancel 6a on both sides

(18 = 18)

Since both sides are equal, there are infinitely many solutions.

You might be interested in

The plans for a shed call for a rectangular floor with a perimeter of 276 ft. the length is two times the width. find the length

hichkok12 [17]

2l+2w=276
l=2w

2(2w)+2w=276
6w=276
w=46
l=92

6 0

3 years ago

The area of the sector of a circle with a radius of 8 centimeters is 125.6 square centimeters. The estimated value of Pi is 3.14

elena55 [62]

Hello there!

The correct answer is C. 225.

Hope This Helps You!
Good Luck :)

6 0

3 years ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

Use distributive property to write the expression withoit parenthesis: 3(7x+4)

zalisa [80]

Answer:

21x + 12

Step-by-step explanation:

correct me of i am wrong

6 0

3 years ago

Read 2 more answers

What’s the circumference of a circle with a diameter of 9 inches? Use 13.14 for n

Oksanka [162]

Answer:

28.26 inches

Step-by-step explanation:

The circumference of a circle is $\pi d$ , where d = diameter. In this case, we use pi as 3.14 and the diameter as 9.

$3.14 * 9$
$28.26$

Therefore, the answer is 28.26.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0

2 years ago

Read 2 more answers