A rocket moves through outer space at 11,000 m/s. At this rate, how much time would be required to travel the distance from Eart
1 answer:
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A) 11.1 cm
We can find the focal length of the lens by using the lens equation:
where
f is the focal length
p = 16.0 cm is the distance of the object from the lens
q = 36.0 cm is the distance of the image from the lens (taken with positive sign since it is on the opposide side to the image, so it is a real image)
Solving the equation for f:
B) Converging
The focal length is:
- Positive for a converging lens
- Negative for a diverging lens
In this case, the focal length is positive, so it is a converging lens.
C) 18.0 mm
The magnification equation states that:
where
is the heigth of the image
is the height of the object
Solving the formula for , we find
So the image is 18 mm high.
D) Inverted
From the magnification equation we have that:
- When the sign of is positive, the image is erect
- When the sign of is negative, the image is inverted
In this case, is negative, so the image is inverted.
Answer:
d= 100m
Explanation:
Cheetah kinematic
The cheetah moves with uniformly accelerated movement, and the formulas that describe this movement are:
d= v₀*t + (1/2)*a*t² Formula (1)
vf²=v₀²+2*a*d Formula (2)
vf=v₀+a*t Formula (3)
Where:
d:distance in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
t: time in seconds (s)
Known Data
v₀ =0
a = 4.5 m/s²
vf= 30 m/s.
Problem development
We apply the formula (2) that has known data to calculate the distance :
vf²=v₀²+2*a*d
(30)²= 0 + 2* 4.5* d
d= 100m