Answer:
i. -4m
ii. 20m
Explanation:
The car travels 8m to the east, then travels 12m to the west which is the opposite of the east. Going west, the car travels 8m back to the origin point and then another 4m due west to make 12m. The displacement from the origin point is -4 (the negative sign shows the direction because displacement is a vector quantity)
Total distance = 8m going east + 8m back to origin + 4m west = 20m
Answer:
The height of the pyramid is approximately 104 Ft. See the graphic attached.
Explanation:
First, you have to plot to realize that you have two rectangle triangles, formed by the different elevation points of view. From there you can have a system of two equations, with two unknown values.
Equation (1)

Equation (2)
![tan 18^{o}10'=\frac{Ph}{x+183} \\\\Ph=[tan 18^{o}10'][x+183]=[0.3281][x+183]](https://tex.z-dn.net/?f=tan%2018%5E%7Bo%7D10%27%3D%5Cfrac%7BPh%7D%7Bx%2B183%7D%20%5C%5C%5C%5CPh%3D%5Btan%2018%5E%7Bo%7D10%27%5D%5Bx%2B183%5D%3D%5B0.3281%5D%5Bx%2B183%5D)
Matching (1) and (2)

replacing x value in (1)

Answer:
The beat frequency is 0.0019 MHz.
Explanation:
Given that,
Velocity = 0.32 m/s
Frequency = 4.40 MHz
Speed of wave = 1540 m/s
We need to calculate the frequency
Case (I),
Observer is moving away from the source
Using Doppler's effect

Where, v' = speed of observer
Put the value into the formula


Case (II),
Cell is as the source of sound of frequency f' and it moving away from the observer.
Using formula of frequency



We need to calculate the beat frequency


Hence, The beat frequency is 0.0019 MHz.
<span>5.98 x 10^-2 ohms.
Resistance is defined as:
R = rl/A
where
R = resistance in ohms
r = resistivity (given as 1.59x10^-8)
l = length of wire.
A = Cross sectional area of wire.
So plugging into the formula, the known values, including the area of a circle being pi*r^2, gives:
R = 1.59x10^-8 * 3.00 / (pi * (5.04 x 10^-4)^2)
R = (4.77 x 10^-8) / (pi * 2.54016 x 10 ^-7)
R = (4.77 x 10^-8) / (7.98015 x 10^-7)
R = 5.98 x 10^-2 ohms
So that wire has a resistance of 5.98 x 10^-2 ohms.</span>