Answer:
t = 6.68 seconds
Explanation:
The acceleration of the automobile, 
Initial speed of the automobile, u = 91 km/hr = 25.27 m/s
Final speed of the automobile, v = 104 km/hr = 28.88 m/s
Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :
t = 6.68 seconds
So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.
Answer:
Option D - 0.2 s
Explanation:
We are given;
Initial velocity; u = 7 m/s
Height of table; h = 1.8m
Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.
Thus;
h = ut + ½gt²
Plugging in the relevant values, we have;
1.8 = 7t + ½(9.8)t²
4.9t² + 7t - 1.8 = 0
Using quadratic formula to find the roots of the equation gives us;
t = -1.65 or 0.22
We can't have negative t value, thus we will pick the positive one.
So, t = 0.22 s
This is approximately 0.2 s
Answer: The word is abstract.
Explanation:
Answer:
pascal
Explanation:
its obtained after either division or multiplication
Answer:
Explanation:
F = ma
4.45g - 2.75g = (4.45 + 2.75)a
a = 9.81(4.45 - 2.75) / (4.45 + 2.75) = 2.31625 ≈ 2.32 m/s²
a)
T = 2.75(9.81 + 2.32) = 33.3 N
or
T = 4.45(9.81 - 2.32) = 33.3 N
b) 2.32 m/s² upward for 2.75 kg mass
2.32 m/s² downward for 4.45 kg mass
c) y = ½at² = ½(2.31625/3)1² = 1.158125 ≈ 1.16 m
