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algol [13]
3 years ago
8

Give a different example of an inverse relationship (not using wavelength or frequency

Physics
1 answer:
ivanzaharov [21]3 years ago
3 0

An example of an inverse relationship is the one between pressure and volume of an ideal gas

Explanation:

Boyle's law states that:

<em>"For a gas kept at a constant temperature, the pressure of the gas is inversely proportional to its volume" </em>

Mathematically,

pV=const.

where p is the pressure of the gas and V its volume.

The relationship can be written as

p\propto \frac{1}{V}

Therefore it is an example of inverse relationship, because:

  • As the volume increases, the pressure decreases
  • As the volume decreases, the pressure increases

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

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The distance between 4 nodes (3 sections, 2 sections= wavelength) is 15.0cm. The frequency of the source is 10Hz. What's the spe
Natalija [7]

Answer:

the speed of the waves is 150 cm/s

Explanation:

Given;

frequency of the wave, f = 10 Hz = 10

distance between 4 nodes, L = 15.0 cm

The wavelength (λ) of the wave is calculated as follows;

Node to Node = λ/2

L = 2(Node to Node) = (4 Nodes) = 2 (λ/2) = λ

Thus, λ = L = 15.0 cm

The speed (v) of the wave is calculated as follows;

v = fλ

v =  10 Hz   x  15.0 cm

v = 150 cm/s

Therefore, the speed of the waves is 150 cm/s

7 0
3 years ago
As a glacier melts, the volume V of the ice, measured in cubic kilometers, decreases at a rate modeled by the differential equat
DaniilM [7]

Answer:

the volume in terms of time t ⇒ \\V = e^{0.05t} + 399\\

Explanation:

Given that :

\frac{dv}{dt}= kv\\\\\int\limits \, \frac{dv}{v}=  \int\limits \, kdt\\In v = kt + C_1\\v = e^{kt} + C\\400 = e^{k*0} + C\\400 = 1 + C\\C = 400 -1\\C = 399

V = e^{kt} + 399

When v = 300 ;  \frac{dv}{dt}= - 15

then

\frac{dv}{dt}= kv\\\\-15 = 300*k\\\\k = \frac{-15}{300}\\\\\\k = \frac{-1}{20}\\\\k = -0.05

∴ \\V = e^{0.05t} + 399\\

Therefore, the volume in terms of time t ⇒ \\V = e^{0.05t} + 399\\

6 0
3 years ago
A 4.0 cm × 4.2 cm rectangle lies in the xy-plane. You may want to review (Pages 664 - 668) . Part A What is the electric flux th
padilas [110]

Answer:

(A). The flux is 0.336 N.m²/C

(B). The flux is zero.

Explanation:

Given that,

Length = 4.2 cm

Width = 4.0 cm

Electric field E=(150 i-200 k)\ N/C

Area vector is perpendicular to xy plane

(A). We need to calculate the flux

Using formula of flux

\phi=E\cdot A

Where, E = electric field

A = area

Put the value into the formula

\phi=(150 i-200 k)\times(4.2\times10^{-2}\times4.0\times10^{-2})k

\phi=-200\times4.2\times10^{-2}\times4.0\times10^{-2}

\phi=-0.336\ N.m^2/C

(B). Given electric field

E=(150i-200j)\ N/C

We need to calculate the flux

Using formula of flux

\phi=E\cdot A

Put the value into the formula

\phi=(150 i-200 j)\times(4.2\times10^{-2}\times4.0\times10^{-2})k

Here, The component of k is not given

So, the flux is

\phi=0

Hence, (A). The flux is -0.336 N.m²/C

(B). The flux is zero.

7 0
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