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4 years ago

35. A daredevil is launched out of a

Physics

1 answer:

Nezavi [6.7K]4 years ago

6 0

Answer:

845 m

Explanation:

Given in the y direction:

v₀ = 0 m/s

a = 10 m/s²

t = 13 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (13 s) + ½ (10 m/s²) (13 s)²

Δy = 845 m

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An object with charge -4.0μC is placed between a positively charged object to the

elena-s [515]

The net force on the -4.0μC object as a result of this net field will be -10.4 N.

<h3>What is the charge?</h3>

The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.

The electric field intensity is found as the force per unit charge.

Electric field intensity on the positive charge:

$\rm E_1 = \frac{F_1}{Q} \\\\\ \rm 1.2 N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_1 = - 4.8 \ N$

Electric field intensity on the negative charge:

$\rm E_2 = \frac{F_2}{Q} \\\\\ \rm 1.4 \ N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_2 = - 5.6 \ N$

The net charge is the algebraic sum of the two charges;

$\rm F_{net}=F_1+F_2 \\\\ F_{net}= -4.8 -5.6 \\\\ F_{net}=-10.4 \ N$

Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.

To learn more about the charge refer to the link;

brainly.com/question/24391667

#SPJ1

4 0

2 years ago

Cheryl is riding on the edge of a merry-go-round, 2m from the center, which is rotating with an increasing angular speed. Cheryl

WINSTONCH [101]

In circular motion we know that there is two type of acceleration that Cheryl experience

1. Tangential acceleration

2. Centripetal acceleration

here given that

$a_t = 3 m/s^2$

for centripetal acceleration we know that

$a_c = \frac{v^2}{R}$

$a_c = \frac{4^2}{2} = 8 m/s^2$

now we know that both centripetal acceleration and tangential acceleration is perpendicular to each other

so total acceleration is vector sum of both and given as

$a_{net} = \sqrt{8^2 + 3^2} = 8.54 m/s^2$

so total acceleration is 8.54 m/s^2

8 0

3 years ago

A hollow conducting sphere with an outer radius of 0.295 m and an inner radius of 0.200 m has a uniform surface charge density o

IrinaK [193]

Answer:

a. $6.032\times10^{-6}C/m^2$

b. $6.816\times10^5N/C$

Explanation:

#Apply surface charge density, electric field, and Gauss law to solve:

a. Surface charge density is defined as charge per area denoted as $\sigma$

$\sigma=\frac{Q}{4\pi r_{out}^2}$ , and the strength of the electric field outside the sphere $E=\frac{\sigma _{new}}{\epsilon _o}$

Using Gauss Law, total electric flux out of a closed surface is equal to the total charge enclosed divided by the permittivity.

$\phi=\frac{Q_{enclosed}}{\epsilon_o}\\\\\sigma=\frac{Q}{4\pi r_{out}^2}\\\\\sigma=\frac{0.370\times 10^{-6}}{4\pi \times (0.295m)^2}\\\\=3.383\times10^{-7}C/m^2$ #surface charge outside sphere.

$\sigma_{new}=\sigma_{s}-\sigma\\\\\sigma_{new}=6.37\times10^{-6}C/m^2-3.383\times10^{-7}C/m^2\\\\\sigma_{new}=6.032\times10^{-6}C/m^2$

Hence, the new charge density on the outside of the sphere is $6.032\times10^{-6}C/m^2$

b. The strength of the electric field just outside the sphere is calculated as:

From a above, we know the new surface charge to be $6.032\times10^{-6}C/m^2$ ,

$E=\frac{\sigma _{new}}{\epsilon _o}\\\\=\frac{6.032\times10^{-6}C/m^2}{\epsilon _o}\\\\\epsilon _o=8.85\times10^{-12}C^2/N.m^2\\\\E=\frac{6.032\times10^{-6}C/m^2}{8.85\times10^{-12}C^2/N.m^2}\\\\E=6.816\times10^5N/C$

Hence, the strength of the electric field just outside the sphere is $6.816\times10^5N/C$

5 0

3 years ago

A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.

denpristay [2]

Answer:

The mass of the rule is 56.41 g

Explanation:

Given;

mass of the object suspended at zero mark, m₁ = 200 g

pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0 22cm 100cm

-------------------------Δ------------------------------------

↓ ↓

200g m₂

Apply principle of moment

(200 g)(22 cm - 0) = m₂(100 cm - 22 cm)

(200 g)(22 cm) = m₂(78 cm)

m₂ = (200 g)(22 cm) / (78 cm)

m₂ = 56.41 g

Therefore, the mass of the rule is 56.41 g

3 0

4 years ago

Use the impulse-momentum theorem to find how long a stone falling straight down takes to increase its speed from 5.6 m/s to 10.6

Nezavi [6.7K]

As stated, the impulse and momentum definitions will be used to later find the value of time through the force of gravity. According to the theory, the impulse formula is given as,

$I = F\Delta t$