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dybincka [34]
3 years ago
15

35. A daredevil is launched out of a

Physics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

845 m

Explanation:

Given in the y direction:

v₀ = 0 m/s

a = 10 m/s²

t = 13 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (13 s) + ½ (10 m/s²) (13 s)²

Δy = 845 m

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This formula equation is unbalanced.
Grace [21]
The answer is:  [C]:  "4" .
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The balanced equation is:
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             P₄ (s) + 6 Cl₂ (g)  <span>→ 4 </span>PCl₃ (l)   .
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6 0
3 years ago
An object is placed at O ona number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to
kvv77 [185]

Answer:

You have a displacement of 5 units to the right.

Explanation:

First you go three to the right which lands on the 3 mark. Then you move it 4 to the left which substracts 4, landing the object at -1. Finally you move 6 to the right, and you finish at marker 5. Since displacement is not total distance but just final distance from the start point directly to end point, it is only a displacement of 5.

6 0
2 years ago
Read 2 more answers
The histogram below shows the number of downloads of a song over time.
Allisa [31]

Given data:

  • It is a graphical display where the data is grouped in to ranges
  • A diagram consists rectangles, whose area is proportional to frequency of a variable and whose width is equal to the class interval.
  • It is an accurate representation of the distribution of numerical data.

<em>From Figure:</em>  

        Each box in the graph (small rectangle box) is assumed to be one download. So, in the graph the time between 8 p.m to 9 p.m, the number of downloads are 8.75 approximately (because the last box is incomplete, therefore 8 complete boxes and 9th is more than half).

<em>So, We conclude that the total number of downloads are approximately 9 in the time span of 8 p.m. to 9 p.m.</em>

7 0
3 years ago
Find the poing of center of gravity<br><br>plz show the steps...​
olasank [31]

Answer:

C

Explanation:

For a uniformly distributed mass, the center of gravity is also the geometric center.  For this shape, the center is at point C.

7 0
3 years ago
A moving car skids to a stop with the wheels locked across a level roadway. Of the forces listed, identify which act on the car.
Vesnalui [34]

Answer:

Normal, Gravity, Friction, and Air Resistance.

Explanation:

When a moving car skid to stop and its wheels are locked across, then the following forces will be applied on the car:

<u>Normal force:</u> It will act counter to gravity that pushes an object against a surface and acts perpendicular to the contact surface.

<u>Gravity:</u> Gravity force acts in each and every object having mass and it can not be avoidable. So, the gravity force will also apply to the car and attract it to the earth's surface.

<u>Friction: </u>Friction is a force that acts opposite to the motion and stops or slows motion. Friction will be applied to the car that will oppose the motion of the car and stop it.

<u>Air resistance:</u> air resistance is defined as the forces exerted by air that acts opposite to the relative motion of an object. Air resistance will also be applied to the car when it will skid to stop as we are always surrounded by the air.

Hence, the correct answers are "Normal, Gravity, Friction, and Air Resistance."

4 0
3 years ago
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