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fomenos
3 years ago
13

What is an effector strain of bacteria

Physics
1 answer:
GarryVolchara [31]3 years ago
7 0
The effector strain of bacteria is that the bacteria would colonize on the teeth and help prevent the child from developing cavitie
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It takes 6 sec for a stone to fall the the bottom of a mineshaft. calculate the
Stels [109]
Ok so this is simple projectile motion problem.

if we have an object falling in free fall it is subject to gravity of -9.80m/s^2

so it says it takes 6 sec to fall and we know initial velocity was zero so we know that h=vt+1/2gt^2 so we get h=0+1/2*9.80*6^2 = 176.4m 

so solving for final speed we get KE=PE = 1/2mv^2=mgh = 1/2v^2=gh so 
v=sqrt(2*g*h) = sqrt(2*9.8*176.4m) = 58.8m/s final speed when it hits the ground


hope this helps you! Thanks!!

8 0
2 years ago
Why does air blows from one place to another​
Maslowich

Air blows from one place to another because gases move from high-pressure areas to low-pressure areas

In simple words

it happens because of pressure differences.

3 0
2 years ago
Read 2 more answers
Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object
Nookie1986 [14]

Explanation:

We have,

The initial position of an object is zero.

The starting velocity is 3 m/s and the final velocity was 10 m/s.

The object moves with constant acceleration..

The area covered under the velocity-time graph gives displacement of the object. The correct option is "the area of the rectangle plus the area of the triangle under the line".

8 0
3 years ago
What is the kinetic energy of a 1,350kg car traveling at a speed of 12m/s?
Ainat [17]
Kinetic energy= 1/2 m v^2

so... 1/2(1350)(12^2)

kinetic energy = 97200Joules
7 0
2 years ago
An automobile starter motor has an equivalent resistance of 0.055 Ï and is supplied by a 12.0 v battery which has a 0.0305 Ï int
LiRa [457]
12 V is the f.e.m. \epsilon of the battery. The potential difference that is applied to the motor is actually the fem minus the voltage drop on the internal resistance r:
\epsilon - Ir
this is equal to the voltage drop on the resistance of the motor R:
RI
so we can write:
\epsilon - Ir = RI
and using r=0.0305~\Omega and R=0.055~\Omega we can find the current I:
I= \frac{\epsilon}{R+r}=140~A
8 0
3 years ago
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