Answer: The height of the fluid rise is 0.01m
Explanation:
Using the equation
h = (2TcosѲ )/rpg
h= height of the fluid rise
diameter of the tube =3mm
radius of the tube= 3/2 =1.5mm=0.0015
T= surface tension = 600mN/m=0.6N/m
Ѳ = contact angle =
C
p= density =3.7g/cm3= 3700kg/m3
g= acceleration due to gravity =9.8m/s2
h = ( 2*0.6*0.5)/(0.0015*3700*9.8)
h = 0.6/54.39
h= 0.01m
Therefore,the height of the fluid rise is 0.01m
The gravitational force between the two objects A) It increases.
Explanation:
The gravitational force between two objects is given by:
(1)
where
G is the gravitational constant
are the masses of the two objects
r is the separation between the objects
In this problem, object A and object B are initially at a distance of
r = 100 m
And at that distance, the force between them is
F
Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:
F' > F
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Answer:

Explanation:
Speed = Distance / Time
So, to find distance, we actually divide distance by rime.
A number of stars that orbit each other bound by gravitational attraction.