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3 years ago

12

Milton purchase a 5 gallon aquarium for his bedroom.to fill the aquarium for his room. To fill the aquarium with water he uses a

container with capacity of 1 quart. How many times will Milton fill amd empty the container before the aquarium is full

1 answer:

svetlana [45]3 years ago

6 0

There a 4 quarts in 1 gallon, so he will fill and empty the container 20 times.

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Consider the equation y = –3(x – 3) Which equation, when graphed with the given equation, will form a system with lines that ove

pentagon [3]

Answer:

y=-3x+9 (D)

Step-by-step explanation:

8 0

3 years ago

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

HELP AGAIN ITS MY LAST QUESTION

Lera25 [3.4K]

Answer:

$\frac{43}{5}, \frac{-7}{5}$

Step-by-step explanation:

6 0

2 years ago

4. Find the value of x.<br> A) 6 √ 2<br> B) 12 √ 3<br> C) 24 √ 3<br> D) 12

Schach [20]

A^2+b^2=c^2
24^2=12^2+x^2
sqrt(576-144)=x
sqrt(432)=x
12sqrt(3)=x
the answer is c

7 0

2 years ago

Read 2 more answers

A side of the triangle below has been extended to form an exterior angle of 164". Find

Arada [10]

Given:

Measure of exterior angle = 164°

The measure of opposite interior angles are x° and 53°.

To find:

The value of x.

Solution:

According to the Exterior Angle Theorem, in a triangle the measure of an exterior angles is always equal to the sum of measures of two opposite interior angles.

Using Exterior Angle Theorem, we get

$x^\circ+53^\circ=164^\circ$

$x^\circ=164^\circ-53^\circ$

$x^\circ=111^\circ$

$x=111$

Therefore, the value of x is 111.

3 0

3 years ago