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sattari [20]
3 years ago
13

The yearbook club had a meeting. The club has 30 people and three fifths of the club showed up for the meeting how many went to

the meeting
Mathematics
2 answers:
cestrela7 [59]3 years ago
8 0

Answer:

there are 45 people in the group

2/3xA=30

2A=30x3

A=90/2

A=45

11Alexandr11 [23.1K]3 years ago
7 0
We know 15 is equal to 1/3 of the value we want to know so the equation where the total number of members equals looks like this 1/3*x. Now divide both sides by 1/3 which equals 15/ (1/3). Dividing by 1/3 is equal to multiplying by 3 so 15 times 3 is 45. So the answer is 45
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What is the answer to 8=56, 7=42, 6=30, 5=20, 3=?
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7 0
3 years ago
The Key Club is having a fundraising dinner for charity. The venue that holds a maximum of 500 people will
Alexus [3.1K]

Answer:

\dfrac{\$1000+\$20x}{x} \leq \$25

Minimum 200 people other than the 2 charity representatives.

Step-by-step explanation:

Given that:

The venue can hold a maximum of 500 people.

Cost of venue = $1000

Per person cost for food = $20

Two charity representatives get to attend the dinner for free.

To find:

The inequality and to determine how many people must come to keep costs at most $25.

Solution:

Let the number of people attending the dinner = x

Cost of food for x people = \$20x

Total cost = $1000 + \$20x

Cost per person = Total cost divided by Number of people attending the dinner.

As per question statement:

\dfrac{\$1000+\$20x}{x} \leq \$25\\\Rightarrow 1000+20x\leq25x\\\Rightarrow 1000 \leq 5x\\\Rightarrow x\geq 200

Therefore, the answer is:

Minimum 200 people other than the 2 charity representatives should attend the dinner.

8 0
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