Answer:
Null hypothesis is: U1 - U2 ≤ 0
Alternative hypothesis is U1 - U2 > 0
Step-by-step explanation:
The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.
Let U1 = mean sales by type A trainees
Let U2 = mean sales by type B trainees
Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0
This implies that type A training does not result in higher mean weekly sales than type B training.
The alternative hypothesis (H1) is: U1 - U2 > 0
This implies that type A training indeed results in higher mean weekly sales than type B training.
Answer:
Step-by-step explanation:
Substitute the value of the variable into the expression and simplify.
Exact Form: a
=
6,
2
3
Decimal Form:
a
=
6
,
0.
¯
6
Let's take any edge length l. The diagonal has length

. In our case it's
Hi there!
5(2f+3)+7
= 10f+15+7
= 10f+22
Hope this helps!
There are 24 positive 2 digit numbers divisible by 4.
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96