Answer:
Step-by-step explanation:
<em>Refer to attached</em>
For the first two of the graphs the minimum number of colors used to color the graph are 3 and for the third one- 5.
So the chromatic numbers are 3 for the first two and 5 for the last one.
Hello from MrBillDoesMath!
Answer:
5
Discussion:
Consider the expansion of e^x:
e^x = 1 + x + x^2/2 + x^3/6 +...... => replace x by 5t
e^(5t) = 1 + (5t) + (5t)^2/2 + .... => subtract 1 from both sides
e^(5t) - 1 = (5t) + (5t)^2/2+.... => divide both sides by t
(e^(5t) -1)/ t = 5 + (25/2) t +....
so as t ends to 0 the quotient tends to
5 + (25/2)0 + (other terms) *0 -> 5
Thank you,
MrB
Number 2. x=5/3 and y=5
number 4. x=7/3 and y=-5
that's all i could answer. and for number 1 x=-3
Assuming you need to find the solution, it's x=3 and y=6
I used elimination
Step-by-step explanation:
{2,3,5,7,9,11,13,15,17,19}
