Answer:
The volume of mercury-contaminated water that has to be consumed to ingest 0.100 g mercury is 2.50 × 10⁴ l
Explanation:
Hi there!
First, let´s convert 0.100 g to mg:
0.100 g · (1000 mg/1 g) = 100 mg
The contaminated water has 0.004 mg per liter, then, we have to find the volume of water that contains 100 mg of mercury:
100 mg · (1 l / 0.004 mg) = 2.50 × 10⁴ l
Then, the volume of mercury-contaminated water ( at a concentration of 0.004 mg/l) that has to be consumed to ingest 0.100 g mercury is 2.50 × 10⁴ l
Have a nice day!
In molten lava like all the rest.
Hope it helped!!!
Quantitative cause it has numbers (quantities). Hope this helps :)
Answer:
The metals are on the bottom left in the periodic table, and the nonmetals are at the top right. The semimetals lie along a diagonal line separating the metals and nonmetals. The elements are arranged in a periodic table, which is probably the single most important learning aid in chemistry.
Explanation:
im not sure if there was supposed to options to that question or not
Hydrogen is usually –1. This is INCORRECT. The oxidation number for H is +1.
Oxygen is usually –2. This is CORRECT.
A pure group 1 element is +1. This is INCORRECT. It does not follow. This will depend on the other elements and the overall charge.
A monatomic ion is 0. This is INCORRECT. Diatomic ion is 0.
