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kakasveta [241]

3 years ago

14

Whivh is the correct mole ratio of K3N to KCI in the chemical reaction

1 answer:

Firlakuza [10]3 years ago

4 0

3.65. The mole ratio from the balanced equation is 2 moles CO2 : 2 moles CO. 2.

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Question 2 (1 point)<br>At the center of the atom is the electron.<br>True<br>False

Stells [14]

Answer:

False the electrons are on the outside of the atoms

Explanation:

5 0

3 years ago

Which of the following coefficients are needed to balance the combustion reaction of ethanol?

djyliett [7]

Answer is: d. 3,2,3.

Balanced chemical reaction: CH₃CH₂OH + 3O₂ → 2CO₂ + 3H₂O.
CH₃CH₂OH is ethanol.
O₂ is molecule of oxygen.
CO₂ is carbon(IV) oxide.
H₂O is water.
There are same number of atoms (oxygen, carbon and hydrogen) on both side of balanced chemical reaction:
2 atoms of carbon.
6 atoms of hydrogen.
7 atoms of oxygen.

5 0

3 years ago

In the following reaction, C6H6)? 2C6H6 + 15O2 12CO2 + 6H2O,

shepuryov [24]

The answer is 27.92g . working is shown in the picture above.

3 0

3 years ago

At the start of a reaction, there are 0.0249 mol N2,

gladu [14]

Answer:

Explanation:

The reaction is given as:

$N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}$

The reaction quotient is:

$Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}$

From the given information:

TO find each entity in the reaction quotient, we have:

$[NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}$

$[N_2] = \dfrac{0.024 }{3.5}$

$[N_2] = 0.006857$

$[H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}$

$[H_2] = 9.17 \times 10^{-3}$

∴

$Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135$

However; given that:

$K_c = 1.2$

By relating $Q_c \ \ and \ \ K_c$ , we will realize that $Q_c \ \ < \ \ K_c$

The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.

7 0

3 years ago

Write the name of the main gases in the air

Delicious77 [7]

Answer:

Nitrogen

Oxygen

Argon

Carbon Dioxide

Methane

Ozone

Explanation:

N₂ accounts for 78% of the atmosphere.

O₂ accounts for 21% of the atmosphere.

Ar accounts for 0.9% of the atmosphere.

CO₂, CH₄, and O₃ only take up 0.1% of the atmosphere.

3 0

3 years ago

Read 2 more answers