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3 years ago

Please help I'm not very sure.

Mathematics

1 answer:

Bogdan [553]3 years ago

5 0

I think it's x2–1=0 because it's the only one that has -1 for origin of the ordinate

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Which values are the solutions to the polynomial equation?<br> 0 = x2 – 18x + 65

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Answer:

If the question is $2x^{2} -18x+65$ then the answer is no real solution. If the question is 2x - 18x + 65 than the answer is -16x+65

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If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] ^2.

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The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All

Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

$C_{n}^{r} =\frac{n!}{r!(n-r)!}$

Where $n=100$ and $r=4$ .

Replacing values, we have

$C_{100}^{4} =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}= \frac{94,109,400}{24}= 3,921,225$

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

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3 years ago

What is the probability that a data value in a normal distribution is between a

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If P(AnB)=2/3 and P(B)=3/4, what is P(A I B)? A.35/36 B.15/16 C.24/25 D.8/9

astraxan [27]

Answer:

$\large\boxed{D.\ \dfrac{8}{9}}$

Step-by-step explanation:

$\text{We know:}\\\\P(A|B)=\dfrac{P(A\ \cap\ B)}{P(B)}\\\\\text{We have:}\\\\P(A\ \cap\ B)=\dfrac{2}{3},\ P(B)=\dfrac{3}{4}.\\\\\text{Substitute:}\\\\P(A|B)=\dfrac{\frac{2}{3}}{\frac{3}{4}}=\dfrac{2}{3}:\dfrac{3}{4}=\dfrac{2}{3}\cdot\dfrac{4}{3}=\dfrac{8}{9}$

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4 years ago