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lesya [120]
3 years ago
6

Tracking scores from past assignments

Physics
2 answers:
svp [43]3 years ago
5 0

The answer is Monitoring progress on edgunity :)

Naddik [55]3 years ago
3 0

Answer:

Monitoring progress

Explanation:

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If you were to stand in the exact center of a rotating disc, you would only have what kind of
Dmitriy789 [7]

Answer:

Tangential speed or Rotational speed

3 0
3 years ago
A 30 N force toward the west is applied to an object. The object moves 50 m east during the time the force is applied. What is t
katovenus [111]

Answer:

D.<u>-1500Joules</u>

Explanation:

The change in kinetic energy of the object s equivalent to the workdone by the body in the west direction (negative x direction)

Workdone = Force * Distance

Given

Force = 30N

Distance moved by the object = 30m

Required

Kinetic energy

Kinetic energy = 30 * 50

Kinetic energy = 1500Joules

Since the body moves in the negative  direction, hence the kinetic energy will be <u>-1500Joules</u>

8 0
3 years ago
Lightning flashes one mile (1609 m) away from you. How much time does it take the light to travel that distance?
hichkok12 [17]

Answer:

t=5.36\times 10^{-6}\ s

Explanation:

Given that,

Lightning flashes one mile (1609 m) away from you.

We need to find the time it take the light to travel that distance. Let the time be t. We know that,

speed = distance/time

t=\dfrac{d}{v}\\\\t=\dfrac{1609}{3\cdot10^{8}}\\\\=5.36\times 10^{-6}\ s

So, the required time is 5.36\times 10^{-6}\ s

7 0
3 years ago
A wire of cross-sectional area 5.00 106 m2 has a resistance of 1.75 O. What is the resistance of a wire of the same material and
MakcuM [25]

Answer:

the resistance of the second wire is 1 ohm.

Explanation:

Given;

cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²

resistance of the first wire, R₁ = 1.75 ohms

cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²

resistance of the second wire, R₂ = ?

The resistance of a wire is given as;

R ∝ \frac{L}{A}

Since the length of the two wires is constant

R₁A₁ = R₂A₂

R_2 = \frac{R_1A_1}{A_2} \\\\R_2 = \frac{1.75\  \times \ 5.00\times 10^6}{8.75\times 10^6} \\\\R_2 = 1 \ ohm

Therefore, the resistance of the second wire is 1 ohm.

6 0
3 years ago
Please help me for brainliest
mihalych1998 [28]

Answer:

was but its six days ago

Explanation:

6 0
3 years ago
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