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lesya [120]
3 years ago
6

Tracking scores from past assignments

Physics
2 answers:
svp [43]3 years ago
5 0

The answer is Monitoring progress on edgunity :)

Naddik [55]3 years ago
3 0

Answer:

Monitoring progress

Explanation:

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Your friend is bragging about his motorcycle. He claims that it can go from a stopped position to 50 miles per hour in three sec
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If the motorcycle can go from 0 to 50mph in 3 seconds the person is describing the motorcycle's acceleration. 
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you're reading from the journal of a European explorer from the early 1600s. In one passage, the explorer describes itting on th
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Answer: horse latitudes

Explanation:

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A motorcycle is following a car that is traveling at a constant speed on a straight highway. Initially, the car and the motorcyc
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Answer:

(a) 3.807 s

(b) 145.581 m

Explanation:

Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.

The distance traveled by car after Δt (seconds) at v_c = 23m/s speed is

s_c = \Delta t v_c = 23\Delta t

The distance traveled by the motorcycle after Δt (seconds) at m_m = 23 m/s speed and acceleration of a = 8 m/s2 is

s_m = \Delta t v_m + a\Delta t^2/2

s_m = 23\Delta t + 8\Delta t^2/2 = 23 \Delta t + 4 \Delta t^2

We know that the motorcycle catches up to the car after Δt, so it must have covered the distance that the car travels, plus their initial distance:

s_m = s_c + 58

23 \Delta t + 4 \Delta t^2 = 23\Delta t + 58

4 \Delta t^2 = 58

\Delta t^2 = 14.5

\Delta t = \sqrt{14.5} = 3.807s

(b)

s_m = 23 \Delta t + 4 \Delta t^2

s_m = 23*3.807 + 58 = 145.581 m

5 0
2 years ago
As a stands, her entire weight is momentarily placed on the heels of her high-heeled shoes. Calculate the pressure exerted on th
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Answer:

Pressure will be 6072449.952Pa

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We have given mass of the women m = 65 kg

Radius of the heels r = 0.578 cm = 0.00578 m

We have to find the pressure

We know that pressure is given by

P=\frac{F}{A}=\frac{mg}{A}

So force F = mg = 65×9.8 = 637 N

Area A=\pi r^2=3.14\times 0.00578^2=1.049\times 10^{-4}m^2

So pressure p=\frac{637}{1.049\times 10^{-4}}=6072449.952Pa

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3 years ago
What would happen if you drop and egg
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It would crack.

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