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lesya [120]
3 years ago
6

Tracking scores from past assignments

Physics
2 answers:
svp [43]3 years ago
5 0

The answer is Monitoring progress on edgunity :)

Naddik [55]3 years ago
3 0

Answer:

Monitoring progress

Explanation:

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Which object is in static equilibrium
balu736 [363]

Answer:

The body is said to be in static equilibrium if the net force acting on a body at rest is zero.As the net force is zero,the body will not undergo motion.

Explanation:

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3 years ago
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On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const
IceJOKER [234]

Answer:

a)

Explanation:

  • Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:

        x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}   (1)

  • Since the car starts from rest, v₀ =0.
  • We know the value of t = 5 sec., but we need to find the value of a.
  • Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

       a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2  (2)

  • Replacing a and t in (1):

       x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}  = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m.  (3)

  • Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
  • Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

       a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2  (4)

  • Replacing v₀, at and t in (1), we have:

       x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m   (5)

  • Therefore, as the truck travels twice as far as the car, the right answer is a).
7 0
3 years ago
Please select the word from the list that best fits the definition
alexdok [17]

Answer:

yuuuhhhhhhh

Explanation:

it maxed Imao

4 0
3 years ago
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Investing in yourself and your career often requires you to “play it safe”.
SashulF [63]

i'd say false, is this for health or lifeskills?

8 0
3 years ago
a car carrying a 80-kgkg test dummy crashes into a wall at 28 m/sm/s and is brought to rest in 0.10 ss. part a what is the magni
iragen [17]

The magnitude of the average force exerted by the seat belt on the dummy is 224N .

<h3>What is an average force ?</h3>

The average force is the force produced by an object moving over a specific period of time at a given rate of speed, or velocity. This velocity is not instantaneous or precisely measured, as the word "average" indicates.

<h3>Briefing:</h3>

mass of the dummy (m) = 80kg

velocity of the dummy (v) = 28 m/s

time (t) = 10 seconds

Average force exerted (F)

To calculate the average force;

According to the formula;

F = (m × v) ÷ t

Where;

F represents the force exerted

m represents the mass of the dummy

v represents the velocity

t represents the time

F = m * v/t

F = 80 *28/10

F = 224

F = 224 N

The force exerted by the seat belt on the dummy is 224N .

To know more about Average force visit:

brainly.com/question/24704743

#SPJ4

7 0
1 year ago
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