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hram777 [196]
3 years ago
8

If Jim could drive a Jetson's flying car at a constant speed of 440 km/hr across oceans and space, approximately how long (in mi

llions of years, in 106 years) would he take to drive to a nearby star that is 12.0 light-years away? Use 9.461 × 1012 km/light-year and 8766 hours per year (365.25 days).
Physics
1 answer:
Makovka662 [10]3 years ago
8 0

Answer:

t = 2.94 x 10⁶ years

Explanation:

The equation used in the case of constant speed is:

s = vt

t = s/v

where,

s = distance = 12 light years

s = (12 light years)(9.461 x 10¹² km/light year) =  113.532 x 10¹² km

v = speed = 440 km/hr

t = time passed = ?

Therefore,

t = (113.532 x 10¹² km)/(440 km/hr)

t = 2.58 x 10¹¹ hr

Now, converting it to years:

t = (2.58 x 10¹¹ hr)(1 year/8766 hr)

t = 2.94 x 10⁶ years

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What is the mass of a truck if it is accelerating at a rate of 5 m/s2 and hits a parked car with a
sineoko [7]

Answer:

<h3>The answer is 2800 kg</h3>

Explanation:

The mass of the truck can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{14000}{5}  \\

We have the final answer as

<h3>2800 kg</h3>

Hope this helps you

5 0
3 years ago
Two forces of 8N and 10N CANNOT give a resultant of<br><br> a. 1 N<br> b. 2 N<br> c. 9 N<br> d. 18 N
Lelechka [254]

Answer:

I believe it is D

forgive me if I'm wrong

5 0
3 years ago
A Ping-Pong ball has a diameter of 2.55 cm and average density of 0.116 g/cm3 . What force would be required to hold it complete
Mrac [35]

Answer:

F = 0.075 N

Explanation:

given,

diameter of ping pong ball = 2.55 cm

average density of the ball = 0.116 g/cm³

Force require to hold the ball completely submerged= ?

Volume of the ball

V = \dfrac{4}{3} \pi r^3

V = \dfrac{4}{3} \pi (\dfrac{2.55}{2})^3

    V = 8.63 cm³

density of water = 1 g/cm³

force required to keep the ball submerged is equal to

F = \rho_w V_w g - \rho_b V g

F = 1\times 8.63\times g - 0.116 \times 8.63 \times g

F = 7.63 x 9.8 x 10⁻³

F = 0.075 N

Force required to keep the ball inside the water is equal to 0.075 N

7 0
4 years ago
A 0.180 kg ball falls 2.5 m. How much work does the force of gravity do on the ball?
kifflom [539]

The amount of work done by the force of gravity on the ball is 4.41 Joules.

<u>Given the following data:</u>

  • Mass of ball = 0.180 kg.
  • Displacement = 2.5 meters.

<u>Scientific data:</u>

  • Acceleration due to gravity = 9.8 m/s^2.

To calculate the amount of work done by the force of gravity on the ball:

<h3>How to calculate work done.</h3>

In Science, work done is calculated by multiplying force and the height or displacement experienced by an object.

Mathematically, work done is given by the formula:

Work\;done = force \times displacement = mgh

Substituting the given parameters into the formula, we have;

Work\;done = 0.180 \times 9.8 \times 2.5

Work done = 4.41 Joules.

Read more on work done here: brainly.com/question/22599382

6 0
2 years ago
A ball is thrown upward at a velocity of 20m/s. What is the velocity after 3 seconds?
Anit [1.1K]

This is a perfect problem to use positive and negative velocities.

Let's call the positive direction the direction that points UP. 
Then the negative direction is the one that points down.

The acceleration of gravity on Earth is 9.8 m/s² down.  That means
that any object with no forces on it except gravity gains 9.8 m/s of
speed downward every second.

OK. Ready to go to work:

The ball's initial velocity is +(up)20.0 m/s .
Every second after the toss, the ball has -(down)9.8 m/s more velocity.

The ball's velocity after 3 seconds is

            +20 + 3(-9.8)  = 

              20  -  29.4  =    - 9.4 m/s .

That means it's velocity at that time is  9.4 m/s pointing down.

6 0
3 years ago
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