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Katena32 [7]
3 years ago
12

When a number is a multiple of 6, what are the possible values for the ones digit?

Mathematics
1 answer:
IceJOKER [234]3 years ago
4 0
I think they would be 12=2, 18=8, 24=4, 30=0, 36=6, etc.
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Variable y varies directly with variable x, and y = 20 when x = 8.
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All you hav to do it plug in what you know

y=20 and x=8

20=8k


divide both sides by 8

20/8=8k/8

and you get 5/2

20/8=5/2

so your answer is 5/2 
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Answer:

\frac{1}{4^{21} }

Step-by-step explanation:

4^{-3*7}

4^{-21}

\frac{1}{4^{21} }

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A true-false quiz with 10 questions was given to a statistics class. Following is the probability distribution for the score of
disa [49]

Answer:

E(X)=\sum_{i=1}^n X_i P(X_i)  

And if we use the values obtained we got:  

E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48  

For this case this value means that the expected score is about 7.48

Step-by-step explanation:

For this case we assume the following probability distribution:

X         5       6         7       8        9        10

P(X)   0.05   0.15  0.33  0.28   0.12   0.07

First we need to find the expected value (first moment) and the second moment in order to find the variance and then the standard deviation.

In order to calculate the expected value we can use the following formula:  

E(X)=\sum_{i=1}^n X_i P(X_i)  

And if we use the values obtained we got:  

E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48  

For this case this value means that the expected score is about 7.48

In order to find the standard deviation we need to find first the second moment, given by :  

E(X^2)=\sum_{i=1}^n X^2_i P(X_i)  

And using the formula we got:  

E(X^2)=(5^2 *0.05)+(6^2 *0.15)+(7^2 *0.33)+(8^2 *0.28)+ (9^2 *0.12 +(10^2 *0.07))=57.46  

Then we can find the variance with the following formula:  

Var(X)=E(X^2)-[E(X)]^2 =57.46-(7.48)^2 =1.5096  

And then the standard deviation would be given by:  

Sd(X)=\sqrt{Var(X)}=\sqrt{1.5096}=1.229  

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