When a number is a multiple of 6, what are the possible values for the ones digit?
1 answer:
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Answer:
The time the patient expected to survive after diagnosis is 29 years.
Step-by-step explanation:
It is provided that the mean survival time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years.
That is,
An individual's predicted survival time is <em>a</em> = 2.8 standard deviations beyond the mean.
Compute the time the patient expected to survive after diagnosis as follows:
Thus, the time the patient expected to survive after diagnosis is 29 years.
I got D.
There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:
1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator
1 - .1131 - .2005 = .6864
Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.
