The vector pq is given by:
pq = q - p = (7.3) - (5.4)
pq = (7-5, 3-4)
pq = (2, -1)
The vector rs is given by:
rs = s - r = (4,1) - (8.6)
rs = (4-8, 1-6)
rs = (-4, -5)
Then, the vector pq + 3rs is given by:
pq + 3rs = (2, -1) + 3 (-4, -5)
pq + 3rs = (2, -1) + (-12, -15)
pq + 3rs = (2-12, -1-15)
pq + 3rs = (-10, -16)
Answer:
The component from the vector pq + 3rs is:
pq + 3rs = (-10, -16)
The answer is 8-x3
When a variable and a number are like that then it is multiplication. The answer to a multiplication problem is called the product. Quotient is the answer to a division problem. :)
Answer:
PQ=36
Step-by-step explanation:
o=114
PQ I named a because it was easier for me and SP I named b.
o=2(a+b)
114=2(3x+3+2x-1)
114=6x+6+4x-2
114=10x+4
10x=114-4
10x=110/:10
x=11
a=3*11+3
a=33+3
a=36
For this, we use simultaneous equations. Let George's page be g, Charlie's be c and Bill's page be b.
First, <span>George's page contains twice as many type words as Bill's.
Thus, g = 2b.
</span><span>Second, Bill's page contains 50 fewer words than Charlie's page.
Thus, b = c - 50.
</span>If each person can type 60 words per minute, after one minute (i.e. when 60 more words have been typed) <span>the difference between twice the number of words on bills page and the number of words on Charlie's page is 210.
We can express that as 2b - c = 210.
Now we need to find b, since it represents Bill's page.
We can substitute b for (c - 50) since b = c - 50, into the equation 2b - c = 210. This makes it 2(c - 50) - c = 210.
We can expand this to 2c - 100 - c = 210.
We can simplify this to c - 100 = 210.
Add 100 to both sides.
c - 100 + 100 = 210 + 100
Then simplify: c = 210 + 100 = 310.
Now that we know c, we can use the first equation to find b.
b = c - 50 = 310 - 50 = 260.
260 is your answer. I don't know where George comes into it. Maybe it's a red herring!</span>