When a number is a multiple of 6, what are the possible values for the ones digit?
1 answer:
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Answer:
a) P(three tails) =
b) P(two tails followed by one head) =
Step-by-step explanation:
coin is tossed three times so, outcome is
HHH, TTT, HTH, THH, HHT, THT, TTH, HTT.
Hence sample space will be
S = {HHH, TTT, HTH, THH, HHT, THT, TTH, HTT}
chance of getting three tails is '1' i.e. TTT
hence,
P(three tails) =
two tails followed by one head is TTH
so, chance of getting that outcome is also '1'
hence,
P(two tails followed by one head) =
