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Lostsunrise [7]
2 years ago
14

Reuben bought 5CDS that were each the same priceIncluding sales tax, he paid a total of \$81.50. Each CD had a tax of $0.60. wha

t was the price of each cs before tax ?
Mathematics
1 answer:
Liula [17]2 years ago
7 0

Answer:

The price of each CD before tax is $15.70

Step-by-step explanation:

Given that:

Number of CDs bought by Reuben = 5

Cost of five CDs = $81.50

Sales tax on each CD = $0.60

Sales tax on 5 CDs = 0.60*5 = $3.00

Price of CDs without tax = 81.50 - 3.00 = $78.50

Price of each CD = \frac{Cost\ of\ CDs}{No.\ of\ CDs}

Price of each CD = \frac{78.50}{5}

Price of each CD = $15.70

Hence,

The price of each CD before sales tax is $15.70

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What is (radical 75 y 19 ) in the simplest form.
Liono4ka [1.6K]

Answer:

7519 is already in the simplest form. It can be written as 3.947368 in decimal form (rounded to 6 decimal places).

Step-by-step explanation:

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2 years ago
A meteorologist has a thermometer that measures the temperature in degrees Celsius. One morning the thermometer reads -2°C, and
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The thing he is measuring is increasing in ferhinhite but in Celsius it is decresing
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3 years ago
Will Mark Brainlest. (find the domain of following relation for the given range) step by step ​
mr_godi [17]

Step-by-step explanation:

I suppose you mean find the range for the following domain. Because when

g(x) is given the value of X

we are trying to solve the output value which is range.

If you want to solve for the domain, the question should give

g(x) = y

and provide the value of y.

X³+X²-X-2

Substitute

X=(-1)

-1+1-(-1)-2

= -1

g(-1)= -1

Substitute

X=(2)

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g(2)= 8

Substitute

X=(1)

1+1-1-2

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5 0
2 years ago
Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o
Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

(c) The middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of seconds for a randomly selected lap.

The random variable <em>X </em>is normally distributed with mean, <em>μ</em> = 129.71 seconds and standard deviation, <em>σ</em> = 2.28 seconds.

Thus, X\sim N(129.71,\ 2.28^{2}).

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

P(X

                   =P(Z

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let <em>x</em> represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of <em>z</em> for the above probability is:

<em>z</em> = -1.88

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let <em>x</em>₁ and <em>x</em>₂ be the values between which the middle 80% of the distribution lie.

That is,

P(x_{1}

The value of <em>z</em> for the above probability is:

<em>z</em> = 1.28

Compute the values of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80               z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63

Thus, the middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

5 0
3 years ago
Simplify to create an equivalent expression.<br> 8(10 - 6q) + 3(-7q- 2)<br> Choose 1 answer:
eduard
Answer: -69q+74

Step by step:
1. Use distributive property.

8⋅10+8(−6q) + 3(−7q − 2)

Multiply 8 • 10 then -6 • 8

80 - 48q + 3(-7q - 2)

2. Use distributive property again.

80 - 48q + 3(-7q - 2)

Multiply -7 • 3 then 3 • -2

80 - 48q -21q - 6

3. Simplify

Subtract 6 from 80 then subtract 21q from -48q.

-69q + 74


8(10 - 6q) + 3(-7q - 2) = -69q + 74
———
I hope this answers your question. :)

7 0
3 years ago
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