The density of a substance is the ratio of its mass and its volume. The mass of the rod is 10,666.67 grams or 10.67 kgs.
<h3>What is the density of a substance?</h3>
The density of a substance is the ratio of its mass and its volume. Therefore we can write,

mass of substance = m kg
density of substance = d kg/m³
volume of that substance = v m³
The length of the rod is 4 meters, therefore, the length of the rod in centimeters will be 400 centimeters. Thus, The mass in terms of density can be written as,

![= [2\cdot \dfrac{2x^{\frac32}}{3}]_0^{400}\\\\= [\dfrac{4x^{\frac32}}{3}]_0^{400}\\\\=[\dfrac{4(400)^{\frac32}}{3}]-[\dfrac{4(0)^{\frac32}}{3}]\\\\= 10,666.\bar6\rm\ grams](https://tex.z-dn.net/?f=%3D%20%5B2%5Ccdot%20%5Cdfrac%7B2x%5E%7B%5Cfrac32%7D%7D%7B3%7D%5D_0%5E%7B400%7D%5C%5C%5C%5C%3D%20%5B%5Cdfrac%7B4x%5E%7B%5Cfrac32%7D%7D%7B3%7D%5D_0%5E%7B400%7D%5C%5C%5C%5C%3D%5B%5Cdfrac%7B4%28400%29%5E%7B%5Cfrac32%7D%7D%7B3%7D%5D-%5B%5Cdfrac%7B4%280%29%5E%7B%5Cfrac32%7D%7D%7B3%7D%5D%5C%5C%5C%5C%3D%2010%2C666.%5Cbar6%5Crm%5C%20grams)
Hence, the mass of the rod is 10,666.67 grams or 10.67 kgs.
Learn more about Density:
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Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
0.600 is ur answer Hopes this helps u.
Answer:
k= -1
Step-by-step explanation:
To find k, use the points and the m =-7 in the slope formula:
