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3 years ago

Help meeeeeee!!!!!!!!!!

Mathematics

1 answer:

Soloha48 [4]3 years ago

6 0

T-m=25
3m=J
275=t+j+m
Matt spent 50 dollars
Jeff spent 150
and Tim spent 75

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Ignacio is going on vacation. He needs to drive 520 miles in 8 hours. What is his average speed in miles per hour?

Gnom [1K]

Answer:

65 miles per hour

Step-by-step explanation:

520 divided by 8

8 0

2 years ago

Read 2 more answers

Which expression is equivalent to -7(y-2)

soldi70 [24.7K]

Hello!

Distributive property: a(b+c)=ab+ac

$a=-7, b=y, c=2$

$-7y-(-7)*2$

Minus and plus sign.

$-7y+7*2$

Then multiply by the numbers.

$7*2=14$

$\boxed{=-7y+14}$

Hope this helps!

Thanks!

Have a great day!

5 0

3 years ago

Joe sold a total of 10 baked goods. Each cookie costs $1.25 and each brownie costs $2.50. Joe made $20 at the bake sale. How man

AURORKA [14]

Answer:

4 cookies

Step-by-step explanation:

Let the number of cookies he sold be c and that of brownies be b.

Assuming that brownies and cookies are the only type of baked goods sold,

b +c= 10 -----(1)

Amount of money received= $20

b(cost of brownie) +c(cost of cookie)= $20

2.50b +1.25c= 20 -----(2)

From (1): b= 10 -c -----(3)

Substitute (3) into (2):

2.50(10 -c) +1.25c= 20

Expand:

2.50(10) +2.50(-c) +1.25c= 20

25 -2.50c +1.25c= 20

-1.25c +25= 20

Being constants to 1 side:

-1.25c= 20 -25

-1.25c= -5

c= -5 ÷(-1.25)

c= 4

Thus, Joe sold 4 cookies.

8 0

2 years ago

jack donates $X per month to charity. Ta the end if 10 months, he had 1250 donated in total. How much did he donate each month

AnnZ [28]

Answer:

He donated $125 per month.

Step-by-step explanation:

$1250 divided by 10 months to figure out how much he payed each month.

4 0

3 years ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$