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UNO [17]
4 years ago
15

To convert 5.25 minutes to seconds, you would use the ratio =

Mathematics
1 answer:
vivado [14]4 years ago
7 0

Answer:

A. True

Step-by-step explanation:

To convert 5.25 minutes to seconds, you would use the ratio =  seconds, you would use the ratio 1 second  60 minutes.

You might be interested in
1.
mote1985 [20]
From the given data points, we can say that the second term is the square of the first term. Also, the third term is the square of the second term. This pattern goes on up to the last term given which is the square of the term prior. To predict the growth over a period of 10 seconds, we just have to square the growth over a period of 9 seconds.
3 0
3 years ago
Help me please :) its very hard
postnew [5]

Answer:

Answer B

Step-by-step explanation:

You need to first find the surface area of the triangular prism.

In order to do that, we need to first know the length of the base of the triangles on both side. So, I used the pythagorean theorem (a²+b²=c²) after making the triangle a right triangle by cutting it in HALF.

a²+b²=c²

a²+2.6²=3²

a²+6.76=9

Subtract 6.76 on both sides

a²=2.24

a=√2.24

a=1.49666295471

Now, we know that the base of HALF of the triangles on both sides of the prism is 1.496......

We need to MULTIPLY this by 2 to get the full length. So, the length of the bases of both triangles is 2.99332590942

The height of the triangles is 2.6

We are going to first find the area of one triangle and multiply it by 2, to get the area of both triangles.

Area of a triangle = base x height ÷ 2

2.6 x 2.99332590942= 7.78264736449

7.78264736449 ÷ 2 = 3.89132368224

3.89132368224 x 2 (because we have 2 triangles) =7.78264736449  cm squared

Now, we know the area of both triangles, but we now need to add the add the surface area of the rectangles in the net.

Area of a rectangle = length x width

We know that all of the three rectangles are equal in size, and that the length of each one of them is 15 cm. However, the width/height of each one is unknown. We will find out the height of each one by looking at the length of the base of the triangle attached to the first one. We know that because of the base of the triangles = 2.99332590942, the width of the attached rectangles are 2.99332590942. We found this using the Pythagorean theroem (look above).

15 x 2.99332590942= 44.8998886413

44.8998886413 x 3 (because we have 3 of the same rectangles)= 134.699665924 cm squared

Now, we must ADD the surface area of the rectangles AND the triangles.

7.78264736449 (triangles) + 134.699665924 (the three rectangles)= 142.482313288 cm squared.

The CLOSEST OPTION to the answer we got is ANSWER B because it is 142.8 cm squared, which is the closest to the answer we got which was 142.482313288 cm squared.

I really hope this helps :)

6 0
3 years ago
Read 2 more answers
What are the solutions to the compound inequality -14<4x-10<6
wariber [46]

Answer:

-1 < x < 4

Step-by-step explanation:

First separated the compound

-14 < 4x - 10

4x - 10 < 6

Then solved for each

-14 < 4x - 10

-4 < 4x

-1 < x

4x - 10 < 6

4x < 16

x < 4

Then put the inequality together (if applicable)

-1 < x < 4

4 0
3 years ago
Find the discriminant of the following equation:
vladimir1956 [14]

Option 1

The discriminant of given equation is 116

<em><u>Solution:</u></em>

We have to find the discriminant of given equation

<em><u>Given equation is:</u></em>

f(x) = 4x^2+6x-5

To find discriminant,

4x^2+6x-5 = 0

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0

<em><u>Discriminant is given by:</u></em>

D = b^2-4ac

On comparing the given quadratic equation 4x^2+6x-5 = 0 with general quadratic equation ax^2+bx+c = 0

a = 4

b = 6

c = -5

<em><u>Substituting in above formula,</u></em>

D = 6^2-4(4)(-5)\\\\D = 36-16(-5)\\\\D = 36+80\\\\D = 116

Thus discriminant of given equation is 116

8 0
3 years ago
A. How many ways can you distribute $4$ different balls among $4$ different boxes? B. How many ways can you distribute $4$ ident
zysi [14]

Answer:

The answer is explained below

Step-by-step explanation:

A. How many ways can you distribute 4 different balls among 4 different boxes

The number of ways in which 4 different balls can be distributed among 4 different boxes is 4^4=256\ ways

B. How many ways can you distribute 4 identical balls among 4 identical boxes?

The number of ways in which 4 identical balls can be distributed among 4 identical boxes = P(4,1) + P(4,2) +P(4,3) + P(4,4) = 1 + 2 + 1 + 1 = 5 ways

Where P(k,n) is the number of partitions that k can be divided into n parts

P(4,1) = 4 = 1

P(4,2) = 1 + 3, 2+2 = 2

P(4,3) = 1 + 1 + 2 = 1

P(4,4) = 1 + 1 + 1 + 1 = 1

C. How many ways can you distribute 4 identical balls among 4 different boxes

The number of ways in which 4 identical balls can be distributed among 4 different boxes = C(4\ ball+4\ box-1,4\ box-1)=C(7,3)=\frac{7!}{(7-3)!3!}=35\ ways

7 0
3 years ago
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