Scientific tests can help determine substances that appear similar but react differently under the same circumstances
hope this helps :)
The answer would be D.
Enzymes activity increases as the temperature increase so, therefore the answer would be D.
but to be fair they all would work.
<h2>Frequency of allele </h2>
Explanation:
Hardy Weinberg Equilibrium is used to calculate the allelic as well as genotypic frequency
Allelic frequency of dominant and recessive allele is represented by p and q respectively whereas genotypic frequency of dominant genotype is represented by
and
respectively
Given:
H allele (p) = hairy heffalump (dominant)
h allele (q) = hairless heffalump (recessive)
36% of heffalump population is hairless represents the % of recessive genotype, hh (
) =36%
Calculation of frequency of the h allele (q) :
Frequency of genotype hh (
) will be: 36/100=0.36 or 0.6*0.6
Frequency of h allele (q) will be 0.6
Catalase is an enzyme, O2 and H2O are substrates, and H2O2 is a reactant.
Catalase is a substrate, O2 and H2O are substrates, and H2O2 is an enzyme.
Catalase is a substrate, O2 and H2O are products, and H2O2 is an enzyme.
<span>Catalase is an enzyme, O2 and H2O are products, and H2O2 is a substrate.</span>