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3 years ago

What is the value of n

Mathematics

2 answers:

Vladimir79 [104]3 years ago

8 0

<h2>Answer:</h2>

<u>The correct option is</u><u> (D) 69</u>

<h2>Step-by-step explanation:</h2>

n = (interior angle of 131° + interior angle of 160°)

From the figure we can see that

The interior angle of angle 131° = 180 - 131 = 49° because the sun of the two angles must be 180 for a straight line

Similarly

The interior angle of angle 160° = 180 - 160 = 20° because the sun of the two angles must be 180 for a straight line

Now the sum of interior angles of a triangles is 180 so n = 49° + 20° = 69°

Crank3 years ago

7 0

Answer:

The correct answer is option D. 69°

Step-by-step explanation:

Points to remember

1). The sum of angles in a linear pair is 180°

2). In a triangle sum of two angles are equal to the exterior angle of third angle

From the figure we can see a triangle in which two exterior angles area given.

<u>To find the value of n</u>

from figure we get,

n = (interior angle of 131° + interior angle of 160°)

interior angle of 131° = 180 - 131 = 49°

interior angle of 160° = 180 - 160 = 20°

n = 49° + 20° = 69°

Therefore the correct answer is option D. 69°

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Read 2 more answers

The lost value of equipment over a period of time is called depreciation. The simplest method for calculating depreciation is s

marshall27 [118]

Answer:

$D= \frac{1}{11} 15966 = 1451.454$

And we can conclude that with this method the depreciation each year is about 1451.454$ for the item analyzed.

And we can construct the following table:

year Depreciation Ramining value

0 X 15966

1 1451.454 14514.545

2 1451.454 13063.091

3 1451.454 11611.638

4 1451.454 10160.183

5 1451.454 8708.729

6 1451.454 7257.275

7 1451.454 5805.821

8 1451.454 4354.367

9 1451.454 2902.913

10 1451.454 1451.454

11 1451.454 0

Step-by-step explanation:

Previous concepts

Straight line depreciation is "the default method used to recognize the carrying amount of a fixed asset evenly over its useful life".

Solution for the problem

We assume that the useful life for this problem is 11 years

For this case we have the following function in terms of th years (n) and the initilal price (x)

$D= \frac{1}{n} x$

For this case we have the following values:

$x = 15966$ represent the initial cost for a item

$n = 11$ the year on which we want to find the depreciation

And if we replace these values into our function we got this:

$D= \frac{1}{11} 15966 = 1451.454$

And we can conclude that with this method the depreciation each year is about 1451.454$ for the item analyzed.

And we can construct the following table:

year Depreciation Ramining value

0 X 15966

1 1451.454 14514.545

2 1451.454 13063.091

3 1451.454 11611.638

4 1451.454 10160.183

5 1451.454 8708.729

6 1451.454 7257.275

7 1451.454 5805.821

8 1451.454 4354.367

9 1451.454 2902.913

10 1451.454 1451.454

11 1451.454 0

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Answer:

Step-by-step explanation:

Hey There!

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