Answer:
Yes, I'm pretty sure it is. That's why I don't click on it!
Answer:
The distance covered by puck A before collision is 
Explanation:
From the question we are told that
The label on the two hockey pucks is A and B
The distance between the two hockey pucks is D 18.0 m
The speed of puck A is 
The speed of puck B is 
The distance covered by puck A is mathematically represented as

=> 
The distance covered by puck B is mathematically represented as

=> 
Since the time take before collision is the same

substituting values

=> 
=> 
Answer:
The minimum angular velocity of the platform what whould the block slides away is w= 2.26 rad/s.
Explanation:
m= 0.265 kg
r= 2.4 m
μ= 0.257
g= 9.8 m/s²
W= m * g
W= 2.597 N
Fr= μ * W
Fr= 0.66 N
∑F = m * ac
W+Fr = m * ac
(W+ Fr) / m = ac
ac= 12.29 m/s²
ac= w² * r
√(ac/r)= w
w= 2.26 rad/s
Given :
The light rays in the incident ray originate at 20º from the surface.
To Find :
The angle for the incident ray.
Solution :
We know angle of incidence is measured from perpendicular to the surface .
So,

Now, we know by law of reflection :
Angle of reflection = Angle of incident

Therefore, the angle of incident and reflection is 70° each.