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melisa1 [442]
3 years ago
6

A ball is projected horizontally with an initial speed of 5.0m/s

Physics
1 answer:
Sladkaya [172]3 years ago
3 0
I've never done phsysicsssjsjshagdsqhxc
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An athlete runs 600 m in 2 minutes and the next 1000 m in 1 minute on the same straight
krek1111 [17]

Answer:

Explanation:

Average speed is found by adding together the total distances traveled by the athlete and divide that total by the total time it took.

Average velocity is vector, which means it includes direction. If the athlete heads one way and then turns around, his displacement might actually be negative! Yikes! Let's look at speed first:

s=\frac{600+1000}{2+1}=\frac{1600}{3}=533\frac{1}{3}\frac{m}{min}

Velocity is the displacements added together divided by the total amount of time it took. The displacement is the same as the distance here, since the athlete did not veer off his straight-path and didn't turn around.

Average velocity = average speed = 533.3 m/min

3 0
3 years ago
What transfers energy in the form of vibrating electric and magnetic fields?
Rashid [163]
Electromagnetic waves are waves that consist of vibrating electric and magnetic fields. They transfer energy through matter or across space. The transfer of energy by electromagnetic waves is called electromagnetic radiation. ... The two vibrating fields together form an electromagnetic wave.
5 0
3 years ago
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Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105
Dovator [93]
It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating). 
<span>All you need is F=(K*Q1*Q2)/r^2 </span>
<span>Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
3 0
3 years ago
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If v lies in the first quadrant and makes an angle Ï/3 with the positive x-axis and |v| = 4, find v in component form.
Alexeev081 [22]

Answer:

v=

Explanation:

We are given that

Magnitude of vector v=\mid v\mid =4

v lies in the first quadrant

\theta=\frac{\pi}{3}

v_x=\mid v\mid cos\theta

v_y=\mid v\mid sin\theta

Substitute the values then we get

v_x=4cos\frac{\pi}{3}

v_x=4\times \frac{1}{2}=2

cos\frac{\pi}{3}=\frac{1}{2}

v_y=4\times sin\frac{\pi}{3}=4\times \frac{\sqrt 3}{2}=2\sqrt 3

sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Therefore, the vector v in component form=

v=

4 0
4 years ago
Hazardous waste is _____.
Natalka [10]

b.....................................................

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