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Leokris [45]
3 years ago
8

If you fall and skid to a stop on a carpeted floor, you can get a rug burn. Much of this discomfort comes from abrasion,but ther

e can also be a real burn where the skin was too hot. How does this happen?
Physics
1 answer:
just olya [345]3 years ago
3 0

Explanation:

When you run, your body has a kinetic energy  and when you fall while running, the friction between the carpet and your foot, transforms the kinetic energy into thermal energy or heat energy. This can even cause, real burn if the skin were too hot.

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Can someone help me?!!!!!
ladessa [460]

Answer:

magnitude: 21.6; direction: 33.7 degrees

Explanation:

When we multiply a vector by a scalar, we have to multiply each component of the vector by the scalar number. In this case, we have

vector: (-3,-2)

Scalar: -6

so the vector multiplied by the scalar will have components

(-3\cdot (-6), -2 \cdot (-6))=(18,12)

The magnitude is given by Pythagorean's theorem:

m=\sqrt{18^2+12^2}=21.6

and the direction is given by the arctan of the ratio between the y-component and the x-component:

\theta = tan^{-1} (\frac{12}{18})=33.7^{\circ}

3 0
3 years ago
Which of the following is a key assumption of the scientific method
lesantik [10]

Answer:

Though you have not gave the choices, I do believe it is “testing”

Explanation:

3 0
3 years ago
A wave x meters long has a speed of y meters per second. The frequency of the wave is
Sergio [31]
The correct answer is (b.) y/x hertz. That is because the formula to get the frequency is f =  v / w. The following values (v=y meters / second; wavelength = x meters) must be substituted to the equation, which leaves you y/x hertz.
6 0
3 years ago
A circular rod with a gage length of 3.5 mm and a diameter of 2.8 cmcm is subjected to an axial load of 68 kN . If the modulus o
Crank

To solve this problem, we will apply the concepts related to the linear deformation of a body given by the relationship between the load applied over a given length, acting by the corresponding area unit and the modulus of elasticity. The mathematical representation of this is given as:

\delta = \frac{PL}{AE}

Where,

P = Axial Load

l = Gage length

A = Cross-sectional Area

E = Modulus of Elasticity

Our values are given as,

l = 3.5m

D = 0.028m

P = 68*10^3 N

E = 200GPa  

A = \frac{\pi}{4}(0.028)^2 \rightarrow 0.0006157m^2

Replacing we have,

\delta = \frac{PL}{AE}

\delta = \frac{( 68*10^3)(3.5)}{(0.0006157)(200*10^9)}

\delta = 0.001932m

\delta = 1.93mm

Therefore the change in length is 1.93mm

7 0
3 years ago
The pressure, p, of water (in pounds per square foot) at a depth of d feet below the surface is given by the formula p=15+15/33d
Viefleur [7K]
The pressure of the water on the diver is given in an expression written as:

<span>p=15+15/33d

where p is the pressure and d is the distance of the diver </span><span>below the surface.

The pressure is calculated as follows:

</span>p=15+15/33(100) = 15.00  pounds per square feet

Therefore, the correct answer is option A.
8 0
3 years ago
Read 2 more answers
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